MyWikiBiz, Author Your Legacy — Tuesday November 26, 2024
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49 bytes removed
, 04:10, 3 December 2008
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| And so on. | | And so on. |
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− | The implication <math>x \Rightarrow y</math> is written <math>(x (y)),\!</math> which can be read "not <math>x\!</math> without <math>y\!</math>" if that helps to remember the form of expression. | + | The implication <math>x \Rightarrow y</math> is written <math>(x (y)),\!</math> which can be read "not <math>x\!</math> without <math>y\!</math>" if that helps to remember what it means. |
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| This corresponds to the logical graph: | | This corresponds to the logical graph: |
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| </pre> | | </pre> |
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− | Thus, the equivalence <math>x \Leftrightarrow y</math> has to be written somewhat inefficiently as a conjunction of to and fro implications: <math>(x (y)) (y (x)).\!</math> | + | Thus, the equivalence <math>x \Leftrightarrow y</math> has to be written somewhat inefficiently as a conjunction of two implications: <math>(x (y)) (y (x)).\!</math> |
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| This corresponds to the logical graph: | | This corresponds to the logical graph: |
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| </pre> | | </pre> |
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− | Putting all the pieces together, the problem given amounts to proving the following equation, expressed in the forms of logical graphs and parenthetical parse strings, respectively: | + | Putting all the pieces together, showing that <math>\lnot (p \Leftrightarrow q)</math> is equivalent to <math>(\lnot q) \Leftrightarrow p</math> amounts to proving the following equation, expressed in the forms of logical graphs and parse strings, respectively: |
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− | * Show that <math>\lnot (p \Leftrightarrow q)</math> is equivalent to <math>(\lnot q) \Leftrightarrow p.</math>
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| <pre> | | <pre> |