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* [http://mathforum.org/kb/plaintext.jspa?messageID=6514666 Solution posted by Jon Awbrey, working in the medium of logical graphs].
* [http://mathforum.org/kb/plaintext.jspa?messageID=6514666 Solution posted by Jon Awbrey, working in the medium of logical graphs].
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<pre>
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Date: 30 Nov 2008, 2:00 AM
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Author: Jon Awbrey
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Subject: Re: logical equivalence problem
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o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o
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Required to show: ~(p <=> q) is equivalent to (~q) <=> p.
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required to show: ~(p <=> q) is equivalent to (~q) <=> p
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In logical graphs, the required equivalence looks like this:
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in logical graphs, the required equivalence looks like this:
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<pre>
q o o p q o
q o o p q o
| | |
| | |
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| \ /
| \ /
@ = @
@ = @
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</pre>
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we have a theorem that says:
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We have a theorem that says:
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<pre>
y o xy o
y o xy o
| |
| |
x @ = x @
x @ = x @
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</pre>
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see: http://www.mywikibiz.com/Logical_graph#C2.__Generation_theorem
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See [http://www.mywikibiz.com/Logical_graph#C2.__Generation_theorem Logical Graph : C<sub>2</sub>. Generation Theorem].
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applying this twice to the left hand side of the required equation:
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Applying this twice to the left hand side of the required equation, we get:
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<pre>
q o o p pq o o pq
q o o p pq o o pq
| | | |
| | | |
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| |
| |
@ = @
@ = @
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</pre>
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by collection, the reverse of distribution, we get:
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By collection, the reverse of distribution, we get:
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<pre>
p q
p q
o o
o o
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\ /
\ /
@
@
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</pre>
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but this is the same result that we get from one application of
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But this is the same result that we get from one application of double negation to the right hand side of the required equation.
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double negation to the right hand side of the required equation.
QED
QED
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Jon Awbrey
Jon Awbrey
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PS. I will copy this to the Inquiry List:
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PS. I will copy this to the [http://stderr.org/pipermail/inquiry/ Inquiry List], since I know it preserves the trees.
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http://stderr.org/pipermail/inquiry/
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since I know it preserves the trees.
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o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o~~~~~~~~~o
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</pre>
===Discussion===
===Discussion===