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MyWikiBiz, Author Your Legacy — Wednesday July 03, 2024
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<pre>
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Clearly, if any relation is (&le;''c'')-regular on one of its domains ''X''<sub>''j''</sub> and also (&ge;''c'')-regular on the same domain, then it must be (=''c'')-regular on the affected domain ''X''<sub>''j''</sub>, in effect, ''c''-regular at ''j''.
Clearly, if any relation is (=<c)-regular on one
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of its domains X_j and also (>=c)-regular on the
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same domain, then it must be (=c)-regular on the
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affected domain X_j, in effect, c-regular at j.
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For example, let G = {r, s, t} and H = {1, ..., 9},
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For example, let ''G'' = {''r'',&nbsp;''s'',&nbsp;''t'} and ''H'' = {1,&nbsp;&hellip;,&nbsp;9}, and consider the 2-adic relation ''F''&nbsp;&sube;&nbsp;''G''&nbsp;&times;&nbsp;''H'' that is bigraphed here:
and consider the 2-adic relation F c G x H that is
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bigraphed here:
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<pre>
 
     r          s          t
 
     r          s          t
 
     o          o          o      G
 
     o          o          o      G
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o  o  o  o  o  o  o  o  o  H
 
o  o  o  o  o  o  o  o  o  H
 
1  2  3  4  5  6  7  8  9
 
1  2  3  4  5  6  7  8  9
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We observe that F is 3-regular at G and 1-regular at H.
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We observe that ''F'' is 3-regular at ''G'' and 1-regular at ''H''.
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===Commentary Note 11.9===
 
===Commentary Note 11.9===
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