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==Turing Machine Example==
 
==Turing Machine Example==
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<font size="3">&#9758;</font> See [[Theme One Program]] for documentation of the cactus graph syntax and the propositional modeling program used below.
    
By way of providing a simple illustration of Cook's Theorem, namely, that &ldquo;Propositional Satisfiability is NP-Complete&rdquo;, I will describe one way to translate finite approximations of turing machines into propositional expressions, using the cactus language syntax for propositional calculus that I will describe in more detail as we proceed.
 
By way of providing a simple illustration of Cook's Theorem, namely, that &ldquo;Propositional Satisfiability is NP-Complete&rdquo;, I will describe one way to translate finite approximations of turing machines into propositional expressions, using the cactus language syntax for propositional calculus that I will describe in more detail as we proceed.
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A turing machine for computing the parity of a bit string is described by means of the following Figure and Table.
 
A turing machine for computing the parity of a bit string is described by means of the following Figure and Table.
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<br>
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{| align="center" border="0" cellspacing="10" style="text-align:center; width:100%"
 
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| [[Image:Parity_Machine.jpg|400px]]
{| align="center" border="0" cellpadding="10"
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|-
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| height="20px" valign="top" | <math>\text{Figure 3.} ~~ \text{Parity Machine}\!</math>
<pre>
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o-------------------------------------------------o
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|                                                 |
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|                     1/1/+1                      |
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|                    -------->                    |
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|               /\ /        \ /\                |
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|      0/0/+1  ^  0          1  ^  0/0/+1      |
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|                \/|\        /|\/                |
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|                  | <-------- |                  |
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|          #/#/-1  |  1/1/+1  |  #/#/-1          |
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|                  |          |                  |
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|                  v          v                  |
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|                  #          *                  |
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|                                                |
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o-------------------------------------------------o
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Figure 21-a. Parity Machine
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</pre>
   
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<pre>
 
<pre>
Table 21-b.  Parity Machine
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Table 4.  Parity Machine
 
o-------o--------o-------------o---------o------------o
 
o-------o--------o-------------o---------o------------o
 
| State | Symbol | Next Symbol | Ratchet | Next State |
 
| State | Symbol | Next Symbol | Ratchet | Next State |
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The output of <math>\mathrm{Stunt}(2)</math> being the symbol that rests under the tape head <math>\mathrm{H}</math> when and if the machine <math>\mathrm{M}</math> reaches one of its resting states, we get the result that <math>\mathrm{Parity}(1) = 1.</math>
 
The output of <math>\mathrm{Stunt}(2)</math> being the symbol that rests under the tape head <math>\mathrm{H}</math> when and if the machine <math>\mathrm{M}</math> reaches one of its resting states, we get the result that <math>\mathrm{Parity}(1) = 1.</math>
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==Work Area==
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<pre>
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DATA 20.  http://forum.wolframscience.com/showthread.php?postid=791#post791
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Let's see how this information about the transformation F,
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arrived at by eyeballing the raw data, comports with what
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we derived through a more systematic symbolic computation.
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The results of the various operator actions that we have just
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computed are summarized in Tables 66-i and 66-ii from my paper,
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and I have attached these as a text file below.
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Table 66-i.  Computation Summary for f<u, v> = ((u)(v))
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o--------------------------------------------------------------------------------o
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|                                                                                |
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| !e!f  =  uv.    1      + u(v).    1      + (u)v.    1      + (u)(v).    0      |
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|                                                                                |
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|  Ef  =  uv. (du  dv)  + u(v). (du (dv)) + (u)v.((du) dv)  + (u)(v).((du)(dv)) |
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|                                                                                |
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|  Df  =  uv.  du  dv  + u(v).  du (dv)  + (u)v. (du) dv  + (u)(v).((du)(dv)) |
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|                                                                                |
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|  df  =  uv.    0      + u(v).  du      + (u)v.      dv  + (u)(v). (du, dv)  |
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|                                                                                |
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|  rf  =  uv.  du  dv  + u(v).  du  dv  + (u)v.  du  dv  + (u)(v).  du  dv  |
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|                                                                                |
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o--------------------------------------------------------------------------------o
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Table 66-ii.  Computation Summary for g<u, v> = ((u, v))
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o--------------------------------------------------------------------------------o
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|                                                                                |
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| !e!g  =  uv.    1      + u(v).    0      + (u)v.    0      + (u)(v).    1      |
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|                                                                                |
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|  Eg  =  uv.((du, dv)) + u(v). (du, dv)  + (u)v. (du, dv)  + (u)(v).((du, dv)) |
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|                                                                                |
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|  Dg  =  uv. (du, dv)  + u(v). (du, dv)  + (u)v. (du, dv)  + (u)(v). (du, dv)  |
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|                                                                                |
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|  dg  =  uv. (du, dv)  + u(v). (du, dv)  + (u)v. (du, dv)  + (u)(v). (du, dv)  |
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|                                                                                |
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|  rg  =  uv.    0      + u(v).    0      + (u)v.    0      + (u)(v).    0      |
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|                                                                                |
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o--------------------------------------------------------------------------------o
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o---------------------------------------o
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|                                      |
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|                  o                  |
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|                  / \                  |
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|                /  \                |
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|                /    \                |
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|              o      o              |
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|              / \    / \              |
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|            /  \  /  \            |
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|            /    \ /    \            |
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|          o      o      o          |
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|          / \    / \    / \          |
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|        /  \  /  \  /  \        |
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|        /    \ /    \ /    \        |
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|      o      o      o      o      |
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|      / \    / \    / \    / \      |
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|    /  \  /  \  /  \  /  \    |
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|    /    \ /    \ /    \ /    \    |
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|  o      o      o      o      o  |
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|  |\    / \    / \    / \    /|  |
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|  | \  /  \  /  \  /  \  / |  |
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|  |  \ /    \ /    \ /    \ /  |  |
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|  |  o      o      o      o  |  |
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|  |  |\    / \    / \    /|  |  |
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|  |  | \  /  \  /  \  / |  |  |
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|  | u |  \ /    \ /    \ /  | v |  |
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|  o---+---o      o      o---+---o  |
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|      |    \    / \    /    |      |
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|      |    \  /  \  /    |      |
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|      | du  \ /    \ /  dv |      |
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|      o-------o      o-------o      |
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|                \    /                |
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|                \  /                |
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|                  \ /                  |
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|                  o                  |
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|                                      |
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o---------------------------------------o
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</pre>
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==Discussion==
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<pre>
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PD = Philip Dutton
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PD: I've been watching your posts.
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PD: I am not an expert on logic infrastructures but I find the posts
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    interesting (despite not understanding much of it).  I am like
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    the diagrams.  I have recently been trying to understand CA's
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    using a particular perspective:  sinks and sources.  I think
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    that all CA's are simply combinations of sinks and sources.
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    How they interact (or intrude into each other's domains)
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    would most likely be a result of the rules (and initial
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    configuration of on or off cells).
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PD: Anyway, to be short, I "see" diamond shapes quite often in
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    your diagrams.  Triangles (either up or down) or diamonds
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    (combination of an up and down triangle) make me think
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    soley of sinks and sources.  I think of the diamond to
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    be a source which, during the course of progression,
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    is expanding (because it is producing) and then starts
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    to act as a sink  (because it consumes) -- and hence the
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    diamond.  I can't stop thinking about sinks and sources in
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    CA's and so I thought I would ask you if there is some way
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    to tie the two worlds together (CA's of sinks and sources
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    together with your differential constructs).
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PD: Any thoughts?
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Yes, I'm hoping that there's a lot of stuff analogous to
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R-world dynamics to be discovered in this B-world variety,
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indeed, that's kind of why I set out on this investigation --
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oh, gee, has it been that long? -- I guess about 1989 or so,
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when I started to see this "differential logic" angle on what
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I had previously studied in systems theory as the "qualitative
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approach to differential equations".  I think we used to use the
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words "attractor" and "basin" more often than "sink", but a source
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is still a source as time goes by, and I do remember using the word
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"sink" a lot when I was a freshperson in physics, before I got logic.
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I have spent the last 15 years doing a funny mix of practice in stats
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and theory in math, but I did read early works by Von Neumann, Burks,
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Ulam, and later stuff by Holland on CA's.  Still, it may be a while
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before I have re-heated my concrete intuitions about them in the
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NKS way of thinking.
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There are some fractal-looking pictures that emerge when
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I turn to "higher order propositional expressions" (HOPE's).
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I have discussed this topic elswhere on the web and can look
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it up now if your are interested, but I am trying to make my
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e-positions somewhat clearer for the NKS forum than I have
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tried to do before.
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But do not hestitate to dialogue all this stuff on the boards,
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as that's what always seems to work the best.  What I've found
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works best for me, as I can hardly remember what I was writing
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last month without Google, is to archive a copy at one of the
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other Google-visible discussion lists that I'm on at present.
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</pre>
      
==Document History==
 
==Document History==
Line 3,069: Line 2,910:  
* http://forum.wolframscience.com/archive/topic/228-1.html
 
* http://forum.wolframscience.com/archive/topic/228-1.html
 
* http://forum.wolframscience.com/showthread.php?threadid=228
 
* http://forum.wolframscience.com/showthread.php?threadid=228
* http://forum.wolframscience.com/printthread.php?threadid=228&perpage=33
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* http://forum.wolframscience.com/printthread.php?threadid=228&perpage=50
 
# http://forum.wolframscience.com/showthread.php?postid=664#post664
 
# http://forum.wolframscience.com/showthread.php?postid=664#post664
 
# http://forum.wolframscience.com/showthread.php?postid=666#post666
 
# http://forum.wolframscience.com/showthread.php?postid=666#post666
12,080

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