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MyWikiBiz, Author Your Legacy — Saturday November 23, 2024
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     *      \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ /
 
     *      \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ /
 
     *    16 .  . 14. 1 . 9 . 1 . 10. 1 . 1 . 1 . 6 . 1 . 2 . 1 . 2 .  . 16
 
     *    16 .  . 14. 1 . 9 . 1 . 10. 1 . 1 . 1 . 6 . 1 . 2 . 1 . 2 .  . 16
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</pre>
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==A108352==
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* [http://oeis.org/wiki/A108352 A108352]
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===Links===
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* Jon Awbrey, [http://stderr.org/pipermail/inquiry/2005-July/002846.html Primal Code Characteristic, n = 1 to 1000]
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* Jon Awbrey, [http://stderr.org/pipermail/inquiry/2005-July/002847.html Primal Code Characteristic, n = 1001 to 2000]
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* Jon Awbrey, [http://stderr.org/pipermail/inquiry/2005-July/002853.html Primal Code Characteristic, n = 2001 to 3000]
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===TeX Array===
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{| align="center"
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|
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<math>\begin{array}{*{10}{l}}
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a(1)
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& = & 1
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& \text{because} & (\circ~ 1)^1
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& = & (\circ~ \varnothing)^1
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& = & 1.
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\\
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a(2)
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& = & 0
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& \text{because} & (\circ~ 2)^k
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& = & (\circ~ 1\!:\!1)^k
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& = & 2,
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& \text{for all}~ k > 0.
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\\
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a(3)
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& = & 2
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& \text{because} & (\circ~ 3)^2
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& = & (\circ~ 2\!:\!1)^2
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& = & 1.
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\\
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a(4)
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& = & 2
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& \text{because} & (\circ~ 4 )^2
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& = & (\circ~ 1\!:\!2)^2
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& = &1.
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\\
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a(5)
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& = & 2
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& \text{because} & (\circ~ 5)^2
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& = & (\circ~ 3\!:\!1)^2
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& = & 1.
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\\
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a(6)
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& = & 0
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& \text{because} & (\circ~ 6)^k
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& = & (\circ~ 1\!:\!1 ~~ 2\!:\!1)^k
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& = & 6,
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& \text{for all}~ k > 0.
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\\
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a(7)
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& = & 2
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& \text{because} & (\circ~ 7)^2
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& = & (\circ~ 4\!:\!1)^1
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& = & 1.
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\\
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a(8)
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& = & 2
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& \text{because} & (\circ~ 8)^2
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& = & (\circ~ 1\!:\!3)^1
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& = & 1.
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\\
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a(9)
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& = & 0
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& \text{because} & (\circ~ 9)^k
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& = & (\circ~ 2\!:\!2)^k
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& = & 9,
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& \text{for all}~ k > 0.
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\\
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a(10)
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& = & 0
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& \text{because} & (\circ~ 10)^k
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& = & (\circ~ 1\!:\!1 ~~ 3\!:\!1)^k
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& = & 10,
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& \text{for all}~ k > 0.
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\end{array}</math>
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|}
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===ASCII===
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<pre>
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Example
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    * a(1) = 1 because (1 o)^1 = ({ } o)^1 = 1.
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    * a(2) = 0 because (2 o)^k = (1:1 o)^k = 2, for all positive k.
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    * a(3) = 2 because (3 o)^2 = (2:1 o)^2 = 1.
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    * a(4) = 2 because (4 o)^2 = (1:2 o)^2 = 1.
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    * a(5) = 2 because (5 o)^2 = (3:1 o)^2 = 1.
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    * a(6) = 0 because (6 o)^k = (1:1 2:1 o)^k = 6, for all positive k.
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    * a(7) = 2 because (7 o)^2 = (4:1 o)^1 = 1.
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    * a(8) = 2 because (8 o)^2 = (1:3 o)^1 = 1.
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    * a(9) = 0 because (9 o)^k = (2:2 o)^k = 9, for all positive k.
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    * a(10) = 0 because (10 o)^k = (1:1 3:1 o)^k = 10, for all positive k.
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    * Detail of calculation for compositional powers of 12:
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    * (12 o)^2 = (1:2 2:1) o (1:2 2:1) = (1:1 2:2) = 18
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    * (12 o)^3 = (1:1 2:2) o (1:2 2:1) = (1:2 2:1) = 12
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    * Detail of calculation for compositional powers of 20:
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    * (20 o)^2 = (1:2 3:1) o (1:2 3:1) = (3:2) = 25
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    * (20 o)^3 = (3:2) o (1:2 3:1) = 1
 
</pre>
 
</pre>
  
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