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, 08:48, 11 January 2010→A108352
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* \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ /
* \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ / \ /
* 16 . . 14. 1 . 9 . 1 . 10. 1 . 1 . 1 . 6 . 1 . 2 . 1 . 2 . . 16
* 16 . . 14. 1 . 9 . 1 . 10. 1 . 1 . 1 . 6 . 1 . 2 . 1 . 2 . . 16
+</pre>
+
+==A108352==
+
+* [http://oeis.org/wiki/A108352 A108352]
+
+===Links===
+
+* Jon Awbrey, [http://stderr.org/pipermail/inquiry/2005-July/002846.html Primal Code Characteristic, n = 1 to 1000]
+* Jon Awbrey, [http://stderr.org/pipermail/inquiry/2005-July/002847.html Primal Code Characteristic, n = 1001 to 2000]
+* Jon Awbrey, [http://stderr.org/pipermail/inquiry/2005-July/002853.html Primal Code Characteristic, n = 2001 to 3000]
+
+===TeX Array===
+
+{| align="center"
+|
+<math>\begin{array}{*{10}{l}}
+a(1)
+& = & 1
+& \text{because} & (\circ~ 1)^1
+& = & (\circ~ \varnothing)^1
+& = & 1.
+\\
+a(2)
+& = & 0
+& \text{because} & (\circ~ 2)^k
+& = & (\circ~ 1\!:\!1)^k
+& = & 2,
+& \text{for all}~ k > 0.
+\\
+a(3)
+& = & 2
+& \text{because} & (\circ~ 3)^2
+& = & (\circ~ 2\!:\!1)^2
+& = & 1.
+\\
+a(4)
+& = & 2
+& \text{because} & (\circ~ 4 )^2
+& = & (\circ~ 1\!:\!2)^2
+& = &1.
+\\
+a(5)
+& = & 2
+& \text{because} & (\circ~ 5)^2
+& = & (\circ~ 3\!:\!1)^2
+& = & 1.
+\\
+a(6)
+& = & 0
+& \text{because} & (\circ~ 6)^k
+& = & (\circ~ 1\!:\!1 ~~ 2\!:\!1)^k
+& = & 6,
+& \text{for all}~ k > 0.
+\\
+a(7)
+& = & 2
+& \text{because} & (\circ~ 7)^2
+& = & (\circ~ 4\!:\!1)^1
+& = & 1.
+\\
+a(8)
+& = & 2
+& \text{because} & (\circ~ 8)^2
+& = & (\circ~ 1\!:\!3)^1
+& = & 1.
+\\
+a(9)
+& = & 0
+& \text{because} & (\circ~ 9)^k
+& = & (\circ~ 2\!:\!2)^k
+& = & 9,
+& \text{for all}~ k > 0.
+\\
+a(10)
+& = & 0
+& \text{because} & (\circ~ 10)^k
+& = & (\circ~ 1\!:\!1 ~~ 3\!:\!1)^k
+& = & 10,
+& \text{for all}~ k > 0.
+\end{array}</math>
+|}
+
+===ASCII===
+
+<pre>
+Example
+
+ * a(1) = 1 because (1 o)^1 = ({ } o)^1 = 1.
+ * a(2) = 0 because (2 o)^k = (1:1 o)^k = 2, for all positive k.
+ * a(3) = 2 because (3 o)^2 = (2:1 o)^2 = 1.
+ * a(4) = 2 because (4 o)^2 = (1:2 o)^2 = 1.
+ * a(5) = 2 because (5 o)^2 = (3:1 o)^2 = 1.
+ * a(6) = 0 because (6 o)^k = (1:1 2:1 o)^k = 6, for all positive k.
+ * a(7) = 2 because (7 o)^2 = (4:1 o)^1 = 1.
+ * a(8) = 2 because (8 o)^2 = (1:3 o)^1 = 1.
+ * a(9) = 0 because (9 o)^k = (2:2 o)^k = 9, for all positive k.
+ * a(10) = 0 because (10 o)^k = (1:1 3:1 o)^k = 10, for all positive k.
+ * Detail of calculation for compositional powers of 12:
+ * (12 o)^2 = (1:2 2:1) o (1:2 2:1) = (1:1 2:2) = 18
+ * (12 o)^3 = (1:1 2:2) o (1:2 2:1) = (1:2 2:1) = 12
+ * Detail of calculation for compositional powers of 20:
+ * (20 o)^2 = (1:2 3:1) o (1:2 3:1) = (3:2) = 25
+ * (20 o)^3 = (3:2) o (1:2 3:1) = 1
</pre>
</pre>
