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Line 4,932: |
| Stated in terms of the conditional probability: | | Stated in terms of the conditional probability: |
| | | |
− | : P(''b''|''m'') = P(''b'')
| + | {| align="center" cellspacing="6" width="90%" |
| + | | <math>\operatorname{P}(\mathrm{b}|\mathrm{m}) ~=~ \operatorname{P}(\mathrm{b})</math> |
| + | |} |
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| From the definition of conditional probability: | | From the definition of conditional probability: |
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− | : P(''b''|''m'') = P(''b'' & ''m'')/P(''m'')
| + | {| align="center" cellspacing="6" width="90%" |
| + | | <math>\operatorname{P}(\mathrm{b}|\mathrm{m}) ~=~ \frac{\operatorname{P}(\mathrm{b}\mathrm{m})}{\operatorname{P}(\mathrm{m})}</math> |
| + | |} |
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| Equivalently: | | Equivalently: |
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− | : P(''b'' & ''m'') = P(''b''|''m'')P(''m'')
| + | {| align="center" cellspacing="6" width="90%" |
| + | | <math>\operatorname{P}(\mathrm{b}\mathrm{m}) ~=~ \operatorname{P}(\mathrm{b}|\mathrm{m})\operatorname{P}(\mathrm{m})</math> |
| + | |} |
| | | |
| Thus we may derive the equivalent statement: | | Thus we may derive the equivalent statement: |
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− | : P(''b'' & ''m'') = P(''b''|''m'')P(''m'') = P(''b'')P(''m'')
| + | {| align="center" cellspacing="6" width="90%" |
| + | | <math>\operatorname{P}(\mathrm{b}\mathrm{m}) ~=~ \operatorname{P}(\mathrm{b}|\mathrm{m})\operatorname{P}(\mathrm{m}) ~=~ \operatorname{P}(\mathrm{b})\operatorname{P}(\mathrm{m})</math> |
| + | |} |
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| And this, of course, is the definition of independent events, as applied to the event of being Black and the event of being a Man. | | And this, of course, is the definition of independent events, as applied to the event of being Black and the event of being a Man. |