Module:Location map/data/United Kingdom London Kensington

Module:Location map/data/United Kingdom London Kensington is a location map definition used to overlay markers and labels on an equirectangular projection map of Kensington. The markers are placed by latitude and longitude coordinates on the default map or a similar map image.

Usage

These definitions are used by the following templates when invoked with parameter "United Kingdom London Kensington":

• Template:Tlx
• Template:Tlx
• Template:Tlx
• Template:Tlx

Map definition

• name = Kensington

  Name used in the default map caption

• image = Location map Kensington.png

  The default map image, without "Image:" or "File:"

• top = 51.5186

  Latitude at top edge of map, in decimal degrees

• bottom = 51.4796

  Latitude at bottom edge of map, in decimal degrees

• left = -0.21

  Longitude at left edge of map, in decimal degrees

• right = -0.1526

  Longitude at right edge of map, in decimal degrees

Precision

Longitude: from West to East this map definition covers 0.0574 degrees.

• At an image width of 200 pixels, that is 0.0003 degrees per pixel.
• At an image width of 1000 pixels, that is 0.0001 degrees per pixel.

Latitude: from North to South this map definition covers 0.039 degrees.

• At an image height of 200 pixels, that is 0.0002 degrees per pixel.
• At an image height of 1000 pixels, that is 0 degrees per pixel.

See also

• Module:Location map/data/UK England
• Module:Location map/data/United Kingdom London
• Module:Location map/data/United Kingdom Greater London

Location map templates

• Template:Location map, to display one mark and label using latitude and longitude
• Template:Location map many, to display up to nine marks and labels
• Template:Location map+, to display an unlimited number of marks and labels

Creating new map definitions

• Template:Location map/Creating a new map definition

---

return {
	name = 'Kensington',
	top = 51.5186,
	bottom = 51.4796,
	left = -0.21,
	right = -0.1526,
	image = 'Location map Kensington.png'
}