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, 21:40, 18 August 2009
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| This is not only a logically equivalent DNF but exactly the same DNF expression that we obtained before, so we have established the given equation <math>\texttt{(} p \texttt{(} q \texttt{))(} p \texttt{(} r \texttt{))} = \texttt{(} p \texttt{(} q r \texttt{))}.</math> Incidentally, one may wish to note that this DNF expression quickly folds into the following form: | | This is not only a logically equivalent DNF but exactly the same DNF expression that we obtained before, so we have established the given equation <math>\texttt{(} p \texttt{(} q \texttt{))(} p \texttt{(} r \texttt{))} = \texttt{(} p \texttt{(} q r \texttt{))}.</math> Incidentally, one may wish to note that this DNF expression quickly folds into the following form: |
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− | {| align="center" cellpadding="8" style="text-align:center; width:90%" | + | {| align="center" cellpadding="8" |
− | | | + | | [[Image:Logical Graph (P Q R , (P)).jpg|500px]] || (34) |
− | <pre>
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− | o-----------------------------------------------------------o
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− | | pqr o-------o---o p |
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− | | \ / |
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− | | \ / |
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− | | \ / |
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− | | @ |
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− | | (p q r, (p)) |
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− | | | | |
− | o-----------------------------------------------------------o
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− | </pre>
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− | | (34) | |
| |} | | |} |
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