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124 bytes added ,  01:08, 3 December 2008
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* Show that <math>\lnot (p \Leftrightarrow q)</math> is equivalent to <math>(\lnot q) \Leftrightarrow p.</math>
 
* Show that <math>\lnot (p \Leftrightarrow q)</math> is equivalent to <math>(\lnot q) \Leftrightarrow p.</math>
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We can translate this into logical graphs by supposing that we have to express everything in terms of negation and conjunction, using parentheses for negation &mdash; that is, "(''x'')" for "not ''x''" &mdash; and simple concatenation for conjunction &mdash; "''xyz''" or "''x y z''" for "''x'' and ''y'' and ''z''".
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We can translate this into logical graphs by supposing that we have to express everything in terms of negation and conjunction, using parentheses for negation and simple concatenation for conjunction, thus:
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The negation <math>\lnot x</math> is written <math>(x).\!</math>
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The conjunction <math>x \land y</math> is written <math>x y.\!</math>
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The conjunction <math>x \land y \land z</math> is written <math>x y z.\!</math>
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Etc.
    
In this form of representation, for historical reasons called the "existential interpretation" of logical graphs, we have the following expressions for basic logical operations:
 
In this form of representation, for historical reasons called the "existential interpretation" of logical graphs, we have the following expressions for basic logical operations:
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The disjunction "''x'' or ''y''" is written "((''x'')(''y''))".
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The disjunction <math>x \lor y</math> is written <math>((x)(y)).\!</math>
    
This corresponds to the logical graph:
 
This corresponds to the logical graph:
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