Changes

Line 2,921: Line 2,921:  
Introduce a suitably generic definition of the extended universe of discourse:
 
Introduce a suitably generic definition of the extended universe of discourse:
   −
: Let <math>U = X_1 \times \ldots \times X_k</math> and <math>\operatorname{E}U = U \times \operatorname{d}U = X_1 \times \ldots \times X_k \times \operatorname{d}X_1 \times \ldots \times \operatorname{d}X_k.</math>
+
: For <math>U = X_1 \times \ldots \times X_k</math>,
 +
 
 +
: let <math>\operatorname{E}U = U \times \operatorname{d}U = X_1 \times \ldots \times X_k \times \operatorname{d}X_1 \times \ldots \times \operatorname{d}X_k.</math>
    
For a proposition <math>f : X_1 \times \ldots \times X_k \to \mathbb{B},</math> the (first order) enlargement of <math>f\!</math> is the proposition <math>\operatorname{E}f : \operatorname{E}U \to \mathbb{B}</math> that is defined by:
 
For a proposition <math>f : X_1 \times \ldots \times X_k \to \mathbb{B},</math> the (first order) enlargement of <math>f\!</math> is the proposition <math>\operatorname{E}f : \operatorname{E}U \to \mathbb{B}</math> that is defined by:
Line 3,083: Line 3,085:  
| &nbsp;
 
| &nbsp;
 
|-
 
|-
| f<sub>0</sub> || f<sub>0000</sub> || 0 0 0 0 || (&nbsp;) || false || 0
+
| f<sub>0</sub>
 +
| f<sub>0000</sub>
 +
| 0 0 0 0
 +
| (&nbsp;)
 +
| false
 +
| 0
 
|-
 
|-
| f<sub>1</sub> || f<sub>0001</sub> || 0 0 0 1 || (x)(y) || neither x nor y || &not;x &and; &not;y
+
| f<sub>1</sub>
 +
| f<sub>0001</sub>
 +
| 0 0 0 1
 +
| (x)(y)
 +
| neither x nor y
 +
| &not;x &and; &not;y
 
|-
 
|-
| f<sub>2</sub> || f<sub>0010</sub> || 0 0 1 0 || (x) y || y and not x || &not;x &and; y
+
| f<sub>2</sub>
 +
| f<sub>0010</sub>
 +
| 0 0 1 0
 +
| (x) y
 +
| y and not x
 +
| &not;x &and; y
 
|-
 
|-
| f<sub>3</sub> || f<sub>0011</sub> || 0 0 1 1 || (x) || not x || &not;x
+
| f<sub>3</sub>
 +
| f<sub>0011</sub>
 +
| 0 0 1 1
 +
| (x)
 +
| not x
 +
| &not;x
 
|-
 
|-
| f<sub>4</sub> || f<sub>0100</sub> || 0 1 0 0 || x (y) || x and not y || x &and; &not;y
+
| f<sub>4</sub>
 +
| f<sub>0100</sub>
 +
| 0 1 0 0
 +
| x (y)
 +
| x and not y
 +
| x &and; &not;y
 
|-
 
|-
| f<sub>5</sub> || f<sub>0101</sub> || 0 1 0 1 || (y) || not y || &not;y
+
| f<sub>5</sub>
 +
| f<sub>0101</sub>
 +
| 0 1 0 1
 +
| (y)
 +
| not y
 +
| &not;y
 
|-
 
|-
| f<sub>6</sub> || f<sub>0110</sub> || 0 1 1 0 || (x, y) || x not equal to y || x &ne; y
+
| f<sub>6</sub>
 +
| f<sub>0110</sub>
 +
| 0 1 1 0
 +
| (x, y)
 +
| x not equal to y
 +
| x &ne; y
 
|-
 
|-
| f<sub>7</sub> || f<sub>0111</sub> || 0 1 1 1 || (x&nbsp;y) || not both x and y || &not;x &or; &not;y
+
| f<sub>7</sub>
 +
| f<sub>0111</sub>
 +
| 0 1 1 1
 +
| (x&nbsp;y)
 +
| not both x and y
 +
| &not;x &or; &not;y
 
|-
 
|-
| f<sub>8</sub> || f<sub>1000</sub> || 1 0 0 0 || x&nbsp;y || x and y || x &and; y
+
| f<sub>8</sub>
 +
| f<sub>1000</sub>
 +
| 1 0 0 0
 +
| x&nbsp;y
 +
| x and y
 +
| x &and; y
 
|-
 
|-
| f<sub>9</sub> || f<sub>1001</sub> || 1 0 0 1 || ((x, y)) || x equal to y || x = y
+
| f<sub>9</sub>
 +
| f<sub>1001</sub>
 +
| 1 0 0 1
 +
| ((x, y))
 +
| x equal to y
 +
| x = y
 
|-
 
|-
| f<sub>10</sub> || f<sub>1010</sub> || 1 0 1 0 || y || y || y
+
| f<sub>10</sub>
 +
| f<sub>1010</sub>
 +
| 1 0 1 0
 +
| y
 +
| y
 +
| y
 
|-
 
|-
| f<sub>11</sub> || f<sub>1011</sub> || 1 0 1 1 || (x (y)) || not x without y || x &rarr; y
+
| f<sub>11</sub>
 +
| f<sub>1011</sub>
 +
| 1 0 1 1
 +
| (x (y))
 +
| not x without y
 +
| x &rarr; y
 
|-
 
|-
| f<sub>12</sub> || f<sub>1100</sub> || 1 1 0 0 || x || x || x
+
| f<sub>12</sub>
 +
| f<sub>1100</sub>
 +
| 1 1 0 0
 +
| x
 +
| x
 +
| x
 
|-
 
|-
| f<sub>13</sub> || f<sub>1101</sub> || 1 1 0 1 || ((x) y) || not y without x || x &larr; y
+
| f<sub>13</sub>
 +
| f<sub>1101</sub>
 +
| 1 1 0 1
 +
| ((x) y)
 +
| not y without x
 +
| x &larr; y
 
|-
 
|-
| f<sub>14</sub> || f<sub>1110</sub> || 1 1 1 0 || ((x)(y)) || x or y .|| x &or; y
+
| f<sub>14</sub>
 +
| f<sub>1110</sub>
 +
| 1 1 1 0
 +
| ((x)(y))
 +
| x or y
 +
| x &or; y
 
|-
 
|-
| f<sub>15</sub> || f<sub>1111</sub> || 1 1 1 1 || ((&nbsp;)) || true || 1
+
| f<sub>15</sub>
 +
| f<sub>1111</sub>
 +
| 1 1 1 1
 +
| ((&nbsp;))
 +
| true
 +
| 1
 
|}
 
|}
 
<br>
 
<br>
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