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Revision as of 18:56, 4 January 2008
, 18:56, 4 January 2008→Commentary Note 11.20: markup
Here, the order of relational composition flows up the page. For convenience, the absolute term ''f'' = "frenchman" has been converted by using the comma functor to give the idempotent representation ‘''f''’ = ''f'', = "frenchman that is ---", and thus it can be taken as a selective from the universe of mankind.
Here, the order of relational composition flows up the page. For convenience, the absolute term ''f'' = "frenchman" has been converted by using the comma functor to give the idempotent representation ‘''f''’ = ''f'', = "frenchman that is ---", and thus it can be taken as a selective from the universe of mankind.
By way of a legend for the figure, we have the following data:
By way of a legend for the figure, we have the following data:
<pre>
| m = J +, K +, L +, M = 1
| m = J +, K +, L +, M = 1
|
|
| (T_065 +, ... +, T_096):L +,
| (T_065 +, ... +, T_096):L +,
| (T_097 +, ... +, T_128):M
| (T_097 +, ... +, T_128):M
</pre>
Now let's see if we can use this picture to make sense of the following statement:
<blockquote>
<p>For instance, if our universe is perfect men, and there are as many teeth to a Frenchman (perfect understood) as there are to any one of the universe, then:</p>
: <p>[''t''][''f''] = [''tf'']</p>
<p>holds arithmetically. (CP 3.76).</p>
</blockquote>
In the lingua franca of statistics, Peirce is saying this:
In the lingua franca of statistics, Peirce is saying this: That if the population of Frenchmen is a "fair sample" of the general population with regard to dentition, then the morphic equation [''tf''] = [''t''][''f''], whose transpose gives [''t''] = [''tf'']/[''f''], is every bite as true as the defining equation in this circumstance, namely, [''t''] = [''tm'']/[''m''].
That if the population of Frenchmen is a "fair sample" of
the general population with regard to dentition, then the
morphic equation ['t'f] = ['t'][f], whose transpose gives
['t'] = ['t'f]/[f], is every bite as true as the defining
equation in this circumstance, namely, ['t'] = ['t'm]/[m].
===Commentary Note 11.21===
===Commentary Note 11.21===
