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MyWikiBiz, Author Your Legacy — Monday September 30, 2024
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Peirce is here observing what we might dub a "contingent morphism" or a "skeptraphotic arrow", if you will.  Provided that a certain condition, to be named and, what is more hopeful, to be clarified in short order, happens to be satisfied, we would find it holding that the "number of" map ''v'' : ''S'' → '''R''' such that ''vs'' = [''s''] serves to preserve the multiplication of relative terms, that is as much to say, the composition of relations, in the form:  [''xy''] = [''x''][''y''].
 
Peirce is here observing what we might dub a "contingent morphism" or a "skeptraphotic arrow", if you will.  Provided that a certain condition, to be named and, what is more hopeful, to be clarified in short order, happens to be satisfied, we would find it holding that the "number of" map ''v'' : ''S'' → '''R''' such that ''vs'' = [''s''] serves to preserve the multiplication of relative terms, that is as much to say, the composition of relations, in the form:  [''xy''] = [''x''][''y''].
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<pre>
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So let us try to uncross Peirce's manifestly chiasmatic encryption of the condition that is called on in support of this preservation.
So let us try to uncross Peirce's manifestly chiasmatic encryption
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of the condition that is called on in support of this preservation.
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Proviso for [''xy''] = [''x''][''y''] —
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<blockquote>
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there are just as many ''x''’s per ''y'' as there are ''per'' things[,] things of the universe …
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</blockquote>
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Proviso for [xy] = [x][y] --
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I have placed angle brackets around a comma that CP shows but CE omits, not that it helps much either way.  So let us resort to the example:
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| there are just as many x's per y
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<blockquote>
| as there are 'per' things<,>
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<p>For instance, if our universe is perfect men, and there are as many teeth to a Frenchman (perfect understood) as there are to any one of the universe, then:</p>
| things of the universe ...
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I have placed angle brackets around
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: <p>[''t''][''f''] =  [''tf'']</p>
a comma that CP shows but CE omits,
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not that it helps much either way.
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So let us resort to the example:
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| For instance, if our universe is perfect men, and there
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<p>holds arithmetically.  (CP 3.76).</p>
| are as many teeth to a Frenchman (perfect understood)
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</blockquote>
| as there are to any one of the universe, then:
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|
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| ['t'][f]  =  ['t'f]
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|
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| holds arithmetically.  (CP 3.76).
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Now that is something that we can sink our teeth into,
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Now that is something that we can sink our teeth into, and trace the bigraph representation of the situation. In order to do this, it will help to recall our first examination of the "tooth of" relation, and to adjust the picture that we sketched of it on that occasion.
and trace the bigraph representation of the situation.
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In order to do this, it will help to recall our first
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examination of the "tooth of" relation, and to adjust
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the picture that we sketched of it on that occasion.
     −
Transcribing Peirce's example, we may let m = "man" and 't' = "tooth of ---".
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Transcribing Peirce's example, we may let m = "man" and ''t'' = "tooth of ---". Then ''v''(''t'') = [''t''] = [''tm'']/[''m''], that is to say, in a universe of perfect human dentition, the number of the relative term "tooth of ---" is equal to the number of teeth of humans divided by the number of humans, that is, 32.
Then 'v'('t') = ['t'] = ['t'm]/[m], that is to say, in a universe of perfect
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human dentition, the number of the relative term "tooth of ---" is equal to
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the number of teeth of humans divided by the number of humans, that is, 32.
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The 2-adic relative term 't' determines a 2-adic relation T c U x V,
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The 2-adic relative term ''t'' determines a 2-adic relation ''T''&nbsp;&sube;&nbsp;''U''&nbsp;&times;&nbsp;''V'', where U and V are two universes of discourse, possibly the same one, that hold among other things all of the teeth and all of the people that happen to be under discussion, respectively.  To make the case as simple as we can and still cover the point, let's say that there are just four people in our initial universe of discourse, and that just two of them are French.  The bigraphic composition below shows all of the pertinent facts of the case.
where U and V are two universes of discourse, possibly the same one,
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that hold among other things all of the teeth and all of the people
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that happen to be under discussion, respectively.  To make the case
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as simple as we can and still cover the point, let's say that there
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are just four people in our initial universe of discourse, and that
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just two of them are French.  The bigraphic composition below shows
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all of the pertinent facts of the case.
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<pre>
 
T_1    T_32  T_33    T_64  T_65    T_96  T_97    T_128
 
T_1    T_32  T_33    T_64  T_65    T_96  T_97    T_128
 
  o  ...  o    o  ...  o    o  ...  o    o  ...  o      U
 
  o  ...  o    o  ...  o    o  ...  o    o  ...  o      U
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     o            o            o            o          V = m = 1
 
     o            o            o            o          V = m = 1
 
     J            K            L            M
 
     J            K            L            M
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</pre>
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Here, the order of relational composition flows up the page.
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Here, the order of relational composition flows up the page. For convenience, the absolute term ''f'' = "frenchman" has been converted by using the comma functor to give the idempotent representation ‘''f''’ = ''f'', = "frenchman that is ---", and thus it can be taken as a selective from the universe of mankind.
For convenience, the absolute term f = "frenchman" has been
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converted by using the comma functor to give the idempotent
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representation 'f' = f, = "frenchman that is ---", and thus
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it can be taken as a selective from the universe of mankind.
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<pre>
 
By way of a legend for the figure, we have the following data:
 
By way of a legend for the figure, we have the following data:
  
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