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<pre>
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Just to be clear about what's being indicated here, it's a visual way of summarizing the following data:
Just to be clear about what's being indicated here,
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it's a visual way of specifying the following data:
     −
  d[pq]
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{| align="center" cellspacing="10" style="text-align:center"
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|
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<math>\begin{array}{rcccccc}
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\operatorname{d}(pq)
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& = & p & \cdot & q & \cdot &
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\texttt{(} \operatorname{d}p \texttt{,} \operatorname{d}q \texttt{)}
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\\[4pt]
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& + & p & \cdot & \texttt{(} q \texttt{)} & \cdot & \operatorname{d}q
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\\[4pt]
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& + & \texttt{(} p \texttt{)} & \cdot & q & \cdot & \operatorname{d}p
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\\[4pt]
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& + & \texttt{(} p \texttt{)} & \cdot & \texttt{(}q \texttt{)} & \cdot & 0
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\end{array}</math>
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|}
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  =
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To understand the extended interpretations, that is, the conjunctions of basic and differential features that are being indicated here, it may help to note the following equivalences:
 
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  p q . (dp, dq)
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  −
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  −
 
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  p (q) . dq
  −
 
  −
  +
  −
 
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  (p) q . dp
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  −
  +
  −
 
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  (p)(q) . 0
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To understand the extended interpretations, that is,
  −
the conjunctions of basic and differential features
  −
that are being indicated here, it may help to note
  −
the following equivalences:
      +
<pre>
 
   (dp, dq)  =  dp + dq  =  dp(dq) + (dp)dq
 
   (dp, dq)  =  dp + dq  =  dp(dq) + (dp)dq
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       dq      =  dp dq  +  (dp)dq
 
       dq      =  dp dq  +  (dp)dq
 +
</pre>
   −
Capping the series that analyzes the proposition pq
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Capping the series that analyzes the proposition <math>pq\!</math> in terms of succeeding orders of linear propositions, Figure&nbsp;26-2 shows the remainder map <math>\operatorname{r}(pq) : \operatorname{E}X \to \mathbb{B},</math> that happens to be linear in pairs of variables.
in terms of succeeding orders of linear propositions,
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Figure 26-2 shows the remainder map r[pq] : EX -> B,
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that happens to be linear in pairs of variables.
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</pre>
      
{| align="center" cellspacing="10" style="text-align:center; width:90%"
 
{| align="center" cellspacing="10" style="text-align:center; width:90%"
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Reading the arrows off the map produces the following data:
 
Reading the arrows off the map produces the following data:
    +
<pre>
 
     r[pq]
 
     r[pq]
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     (p)(q) . dp dq
 
     (p)(q) . dp dq
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</pre>
   −
In short, r[pq] is a constant field,
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In short, <math>\operatorname{r}(pq)</math> is a constant field, having the value <math>\operatorname{d}p~\operatorname{d}q</math> at each cell.
having the value dp dq at each cell.
      
A more detailed presentation of Differential Logic can be found here:
 
A more detailed presentation of Differential Logic can be found here:
   −
DLOG D.  http://stderr.org/pipermail/inquiry/2003-May/thread.html#478
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* DLOG D.  http://stderr.org/pipermail/inquiry/2003-May/thread.html#478
DLOG D.  http://stderr.org/pipermail/inquiry/2003-June/thread.html#553
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* DLOG D.  http://stderr.org/pipermail/inquiry/2003-June/thread.html#553
DLOG D.  http://stderr.org/pipermail/inquiry/2003-June/thread.html#571
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* DLOG D.  http://stderr.org/pipermail/inquiry/2003-June/thread.html#571
</pre>
      
==Document History==
 
==Document History==
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