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Revision as of 17:09, 12 June 2009
, 17:09, 12 June 2009→Note 2: markup
==Note 2==
==Note 2==
We have just met with the fact that the differential of the '''''and''''' is the '''''or''''' of the differentials.
{| align="center" cellpadding="6" width="90%"
| align="center" |
<math>p ~\operatorname{and}~ q \quad \xrightarrow{~\operatorname{Diff}~} \quad \operatorname{d}p ~\operatorname{or}~ \operatorname{d}p</math>
|-
| align="center" |
<pre>
<pre>
o-------------------------------------------------o
o-------------------------------------------------o
| |
| |
| p q --Diff--> ((dp) (dq)) |
| p q --Diff--> ((dp) (dq)) |
o-------------------------------------------------o
o-------------------------------------------------o
</pre>
|}
<pre>
It will be necessary to develop a more refined analysis of
It will be necessary to develop a more refined analysis of
this statement directly, but that is roughly the nub of it.
this statement directly, but that is roughly the nub of it.
