MyWikiBiz, Author Your Legacy — Wednesday May 01, 2024
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, 01:40, 29 May 2009
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− | <pre> | + | The Figure shows the points of the extended universe <math>\operatorname{E}U = X \times Y \times \operatorname{d}X \times \operatorname{d}Y</math> that satisfy the difference proposition <math>\operatorname{D}f,</math> namely, these: |
− | This really just constitutes a depiction of
| |
− | the interpretations in EU = X x Y x dX x dY
| |
− | that satisfy the difference proposition Df, | |
− | namely, these: | |
| | | |
− | 1. x y dx dy | + | {| align="center" cellpadding="6" |
− | 2. x y dx (dy) | + | | |
− | 3. x y (dx) dy | + | <math>\begin{array}{rcccc} |
− | 4. x (y)(dx) dy | + | 1. & x & y & dx & dy |
− | 5. (x) y dx (dy) | + | \\ |
− | 6. (x)(y) dx dy | + | 2. & x & y & dx & (dy) |
| + | \\ |
| + | 3. & x & y & (dx) & dy |
| + | \\ |
| + | 4. & x & (y) & (dx) & dy |
| + | \\ |
| + | 5. & (x) & y & dx & (dy) |
| + | \\ |
| + | 6. & (x) & (y) & dx & dy |
| + | \end{array}</math> |
| + | |} |
| | | |
− | By inspection, it is fairly easy to understand Df
| + | An inspection of these six points should make it easy to understand <math>\operatorname{D}f</math> as telling you what you have to do from each point of <math>U\!</math> in order to change the value borne by the proposition <math>f(x, y).\!</math> |
− | as telling you what you have to do from each point | |
− | of U in order to change the value borne by f(x, y). | |
− | </pre> | |
| | | |
| ====Note 4==== | | ====Note 4==== |