MyWikiBiz, Author Your Legacy — Tuesday November 19, 2024
Jump to navigationJump to search
182 bytes added
, 15:32, 19 March 2009
Line 2,572: |
Line 2,572: |
| | | |
| ====Output Conditions for Tape Input "0"==== | | ====Output Conditions for Tape Input "0"==== |
| + | |
| + | Let <math>p_0\!</math> be the proposition that we get by conjoining the proposition that describes the initial conditions for tape input "0" with the proposition that describes the truncated turing machine <math>\operatorname{Stunt}(2).</math> As it turns out, <math>p_0\!</math> has a single satisfying interpretation, and this is represented as a singular proposition in terms of its positive logical features in the following display: |
| + | |
| + | <br> |
| | | |
| <pre> | | <pre> |
− | Let P_0 be the proposition that we get by conjoining
| |
− | the proposition that describes the initial conditions
| |
− | for tape input "0" with the proposition that describes
| |
− | the truncated turing machine Stunt(2). As it turns out,
| |
− | P_0 has a single satisfying interpretation, and this is
| |
− | represented as a singular proposition in terms of its
| |
− | positive logical features in the following display:
| |
− |
| |
| o-------------------------------------------------o | | o-------------------------------------------------o |
| | | | | | | |
Line 2,601: |
Line 2,597: |
| | | | | | | |
| o-------------------------------------------------o | | o-------------------------------------------------o |
| + | </pre> |
| + | |
| + | <br> |
| | | |
| The Output Conditions for Tape Input "0" can be read as follows: | | The Output Conditions for Tape Input "0" can be read as follows: |
Line 2,622: |
Line 2,621: |
| At the time p_2, cell r_2 contains "#". | | At the time p_2, cell r_2 contains "#". |
| | | |
− | The output of Stunt(2) being the symbol that rests under | + | The output of <math>\operatorname{Stunt}(2)</math> being the symbol that rests under the tape head <math>\operatorname{H}</math> if and when the machine <math>\operatorname{M}</math> reaches one of its resting states, we get the result that <math>\operatorname{Parity}(0) = 0.</math> |
− | the tape head H if and when the machine M reaches one of | |
− | its resting states, we get the result that Parity(0) = 0. | |
− | </pre> | |
| | | |
| ====Output Conditions for Tape Input "1"==== | | ====Output Conditions for Tape Input "1"==== |