MyWikiBiz, Author Your Legacy — Wednesday November 20, 2024
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, 19:36, 13 March 2009
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| ==Note 22== | | ==Note 22== |
| | | |
− | <pre>
| + | To see how each finite approximation to a given turing machine can be given a purely propositional description, one fixes the parameter <math>k\!</math> and limits the rest of the discussion to describing <math>\operatorname{Stilt}(k),</math> which is not really a full-fledged TM anymore but just a finite automaton in disguise. |
− | To see how each finite approximation to a given turing machine | |
− | can be given a purely propositional description, one fixes the | |
− | parameter k and limits the rest of the discussion to describing | |
− | Stilt(k), which is not really a full-fledged TM anymore but just | |
− | a finite automaton in disguise. | |
| | | |
− | In this example, for the sake of a minimal illustration, | + | In this example, for the sake of a minimal illustration, we choose <math>k = 2,\!</math> and discuss <math>\operatorname{Stunt}(2).</math> Since the zeroth tape cell and last tape cell are both occupied by the character <math>^{\backprime\backprime}\texttt{\#}^{\prime\prime}</math> that is used for both the ''beginning of file'' <math>(\operatorname{bof})</math> and ''end of file'' <math>(\operatorname{eof})</math> markers, this allows for only one digit of significant computation. |
− | we choose k = 2, and discuss Stunt(2). Since the zeroth | |
− | tape cell and the last tape cell are occupied with the | |
− | bof and eof marks "#", this amounts to only one digit | |
− | of significant computation. | |
| | | |
| + | <pre> |
| To translate Stunt(2) into propositional form we | | To translate Stunt(2) into propositional form we |
| use the following collection of basic propositions, | | use the following collection of basic propositions, |