MyWikiBiz, Author Your Legacy — Thursday December 11, 2025
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, 17:54, 10 March 2009
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| | When the term is being used with its more exact sense, a ''differential'' is a locally linear approximation to a function, in the context of this logical discussion, then, a locally linear approximation to a proposition. | | When the term is being used with its more exact sense, a ''differential'' is a locally linear approximation to a function, in the context of this logical discussion, then, a locally linear approximation to a proposition. |
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| − | I think that it would be best to just go ahead and exhibit the simplest form of a differential <math>\operatorname{d}F\!</math> for the current example of a logical transformation <math>F,\!</math> after which the majority of the easiest questions will have been answered in visually intuitive terms. | + | Recall the form of the current example: |
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| | + | {| align="center" cellpadding="8" width="90%" |
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| | + | <math>\begin{array}{lllll} |
| | + | F & = & (f, g) & = & ( ~\texttt{((u)(v))}~ , ~\texttt{((u,~v))}~ ). |
| | + | \end{array}</math> |
| | + | |} |
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| | + | To speed things along, I will skip a mass of motivating discussion and just exhibit the simplest form of a differential <math>\operatorname{d}F\!</math> for the current example of a logical transformation <math>F,\!</math> after which the majority of the easiest questions will have been answered in visually intuitive terms. |
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| | For <math>F = (f, g)\!</math> we have <math>\operatorname{d}F = (\operatorname{d}f, \operatorname{d}g),</math> and so we can proceed componentwise, patching the pieces back together at the end. | | For <math>F = (f, g)\!</math> we have <math>\operatorname{d}F = (\operatorname{d}f, \operatorname{d}g),</math> and so we can proceed componentwise, patching the pieces back together at the end. |