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MyWikiBiz, Author Your Legacy — Saturday September 28, 2024
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→‎Note 13: \texttt
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A sketch of this work is presented in the following series of Figures, where each logical proposition is expanded over the basic cells <math>\texttt{uv}, \texttt{u(v)}, \texttt{(u)v}, \texttt{(u)(v)}</math> of the 2-dimensional universe of discourse <math>U^\circ = [u, v].\!</math>
 
A sketch of this work is presented in the following series of Figures, where each logical proposition is expanded over the basic cells <math>\texttt{uv}, \texttt{u(v)}, \texttt{(u)v}, \texttt{(u)(v)}</math> of the 2-dimensional universe of discourse <math>U^\circ = [u, v].\!</math>
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<pre>
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===Computation Summary for <math>f(u, v) = \texttt{((u)(v))}</math>===
Computation Summary for f<u, v> = ((u)(v))
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Figure 1.1 expands f = ((u)(v)) over [u, v] to produce
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Figure&nbsp;1.1 is a venn diagram that show how the proposition <math>f = \texttt{((u)(v))}</math> can be expanded over the universe of discourse <math>[u, v]\!</math> to produce a logically equivalent exclusive disjunction, namely, <math>\texttt{uv~+~u(v)~+~(u)v}.</math>
the equivalent exclusive disjunction uv + u(v) + (u)v.
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<pre>
 
o---------------------------------------o
 
o---------------------------------------o
 
|```````````````````````````````````````|
 
|```````````````````````````````````````|
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o---------------------------------------o
 
o---------------------------------------o
 
Figure 1.1.  f = ((u)(v))
 
Figure 1.1.  f = ((u)(v))
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</pre>
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Figure 1.2 expands Ef = ((u + du)(v + dv)) over [u, v] to give:
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Figure&nbsp;1.2 expands Ef = ((u + du)(v + dv)) over [u, v] to give:
    
uv.(du dv) + u(v).(du (dv)) + (u)v.((du) dv) + (u)(v).((du)(dv))
 
uv.(du dv) + u(v).(du (dv)) + (u)v.((du) dv) + (u)(v).((du)(dv))
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<pre>
 
o---------------------------------------o
 
o---------------------------------------o
 
|```````````````````````````````````````|
 
|```````````````````````````````````````|
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o---------------------------------------o
 
o---------------------------------------o
 
Figure 1.2.  Ef = ((u + du)(v + dv))
 
Figure 1.2.  Ef = ((u + du)(v + dv))
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</pre>
    
Figure 1.3 expands Df = f + Ef over [u, v] to produce:
 
Figure 1.3 expands Df = f + Ef over [u, v] to produce:
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uv.du dv + u(v).du(dv) + (u)v.(du)dv + (u)(v).((du)(dv))
 
uv.du dv + u(v).du(dv) + (u)v.(du)dv + (u)(v).((du)(dv))
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<pre>
 
o---------------------------------------o
 
o---------------------------------------o
 
|```````````````````````````````````````|
 
|```````````````````````````````````````|
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o---------------------------------------o
 
o---------------------------------------o
 
Figure 1.3.  Df = f + Ef
 
Figure 1.3.  Df = f + Ef
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</pre>
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I'll break this here in case anyone wants
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I'll break this here in case anyone wants to try and do the work for <math>g\!</math> on their own.
to try and do the work for g on their own.
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</pre>
      
==Note 14==
 
==Note 14==
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