MyWikiBiz, Author Your Legacy — Sunday October 20, 2024
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, 16:05, 8 March 2009
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| would account for the finite protocol of states that we observed the system <math>X\!</math> passing through, as spied in the light of its boolean state variable <math>x : X \to \mathbb{B},</math> and that rule is well-formulated in any of these styles of notation: | | would account for the finite protocol of states that we observed the system <math>X\!</math> passing through, as spied in the light of its boolean state variable <math>x : X \to \mathbb{B},</math> and that rule is well-formulated in any of these styles of notation: |
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− | <pre>
| + | {| align="center" cellpadding="8" width="90%" |
− | 1.1. f : B -> B such that f : x ~> (x) | + | | 1.1. || <math>f : \mathbb{B} \to \mathbb{B}</math> such that <math>f : x \mapsto \underline{(}~ x ~\underline{)}</math> |
| + | |- |
| + | | 1.2. || <math>x' ~=~ \underline{(}~ x ~\underline{)}</math> |
| + | |- |
| + | | 1.3. || <math>x ~:=~ \underline{(}~ x ~\underline{)}</math> |
| + | |- |
| + | | 1.4. || <math>dx ~=~ 1</math> |
| + | |} |
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− | 1.2. x' = (x)
| + | In the current example, we already know in advance the program that generates the state transitions, and it is a rule of the following equivalent and easily derivable forms: |
− | | |
− | 1.3. x := (x)
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− | | |
− | 1.4. dx = 1
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− | | |
− | In the current example, having read the manual first, | |
− | I guess, we already know in advance the program that
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− | generates the state transitions, and it is a rule of | |
− | the following equivalent and easily derivable forms: | |
| | | |
| + | <pre> |
| 2.1. F : B^2 -> B^2 such that F : <u, v> ~> <((u)(v)), ((u, v))> | | 2.1. F : B^2 -> B^2 such that F : <u, v> ~> <((u)(v)), ((u, v))> |
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