MyWikiBiz, Author Your Legacy — Tuesday September 09, 2025
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, 22:44, 5 March 2009
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− | <pre> | + | Maintaining a strict analogy with ordinary difference calculus would perhaps have us write <math>\operatorname{D}G_j = \operatorname{E}G_j - G_j,</math> but the sum and difference operations are the same thing in boolean arithmetic. It is more often natural in the logical context to consider an initial proposition <math>q,\!</math> then to compute the enlargement <math>\operatorname{E}q,</math> and finally to determine the difference <math>\operatorname{D}q = q + \operatorname{E}q,</math> so we let the variant order of terms reflect this sequence of considerations. |
− | DG_1 = G_1 <u, v> + EG_1 <u, v, du, dv>
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− | = G_1 <u, v> + G_1 <u + du, v + dv>
| + | Given these general considerations about the operators <math>\operatorname{E}</math> and <math>\operatorname{D},</math> let's return to particular cases, and carry out the first order analysis of the transformation <math>F(u, v) ~=~ ( ~\underline{((}~ u ~\underline{)(}~ v ~\underline{))}~ , ~\underline{((}~ u ~,~ v ~\underline{))}~ ).</math> |
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− | DG_2 = G_2 <u, v> + EG_2 <u, v, du, dv>
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− | | |
− | = G_2 <u, v> + G_2 <u + du, v + dv>
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− | | |
− | Maintaining a strict analogy with ordinary difference calculus
| |
− | would perhaps have us write DG_j = EG_j - G_j, but the sum and
| |
− | difference operations are the same thing in boolean arithmetic.
| |
− | It is more often natural in the logical context to consider an
| |
− | initial proposition q, then to compute the enlargement Eq, and
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− | finally to determine the difference Dq = q + Eq, so we let the
| |
− | variant order of terms reflect this sequence of considerations.
| |
− | | |
− | Given these general considerations about the operators E and D, | |
− | let's return to particular cases, and carry out the first order | |
− | analysis of the transformation F<u, v> = <((u)(v)), ((u, v))>. | |
− | </pre> | |
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| ==Note 11== | | ==Note 11== |