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MyWikiBiz, Author Your Legacy — Thursday September 26, 2024
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Let us now consider the family of <math>4^\text{th}\!</math> gear curves through the extended space <math>\operatorname{E}^4 X = \langle x, dx, d^2 x, d^3 x, d^4 x \rangle.</math>  These are the trajectories that are generated subject to the law <math>d^4 x = 1,\!</math> where it is understood in making such a statement that all higher order differences are equal to <math>0.\!</math>
 
Let us now consider the family of <math>4^\text{th}\!</math> gear curves through the extended space <math>\operatorname{E}^4 X = \langle x, dx, d^2 x, d^3 x, d^4 x \rangle.</math>  These are the trajectories that are generated subject to the law <math>d^4 x = 1,\!</math> where it is understood in making such a statement that all higher order differences are equal to <math>0.\!</math>
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<pre>
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Since <math>d^4 x\!</math> and all higher order <math>d^j x\!</math> are fixed, the entire dynamics can be plotted in the extended space <math>\operatorname{E}^3 X = \langle x, dx, d^2 x, d^3 x \rangle.</math> Thus, there is just enough room in a planar venn diagram to plot both orbits and to show how they partition the points of <math>\operatorname{E}^3 X.</math>  As it turns out, there are exactly two possible orbits, of eight points each, as illustrated in Figures&nbsp;16-a and 16-b.  See here:
Since d^4.x and all higher order d^j.x are fixed, the entire dynamics
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can be plotted in the extended space E^3.X = <|x, dx, d^2.x, d^3.x|>.
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Thus, there is just enough room in a planar venn diagram to plot all
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of these orbits and to show how they partition the points of E^3.X.
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As it turns out, there are exactly two possible orbits, of eight
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points each, as illustrated in Figures 16-a and 16-b.  See here:
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DLOG D23.  http://stderr.org/pipermail/inquiry/2003-May/000502.html
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:* [http://stderr.org/pipermail/inquiry/2003-May/000502.html DLOG D23]
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Zoom^4 ...
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<math>\operatorname{Zoom}^4\ \ldots</math>
</pre>
      
==Note 7==
 
==Note 7==
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