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→‎Stretching Exercises: mathematical markup
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For each choice of propositions <math>p\!</math> and <math>q\!</math> about things in <math>X,\!</math> the stretch of <math>F\!</math> to <math>p\!</math> and <math>q\!</math> on <math>X\!</math> is just another proposition about things in <math>X,\!</math> a simple proposition in its own right, no matter how complex its current expression or its present construction as <math>F^\$ (p, q) = \underline{(}~p~,~q~\underline{)}^\$</math> makes it appear in relation to <math>p\!</math> and <math>q.\!</math>  Like any other proposition about things in <math>X,\!</math> it indicates a subset of <math>X,\!</math> namely, the fiber that is variously described in the following ways:
 
For each choice of propositions <math>p\!</math> and <math>q\!</math> about things in <math>X,\!</math> the stretch of <math>F\!</math> to <math>p\!</math> and <math>q\!</math> on <math>X\!</math> is just another proposition about things in <math>X,\!</math> a simple proposition in its own right, no matter how complex its current expression or its present construction as <math>F^\$ (p, q) = \underline{(}~p~,~q~\underline{)}^\$</math> makes it appear in relation to <math>p\!</math> and <math>q.\!</math>  Like any other proposition about things in <math>X,\!</math> it indicates a subset of <math>X,\!</math> namely, the fiber that is variously described in the following ways:
   −
<pre>
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{| align="center" cellpadding="4" style="text-align:left" width="90%"
[| F^$ (p, q) |] = [| -(p, q)-^$ |]
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| &nbsp;
 
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|-
                  = (F^$ (p, q))^(-1)(%1%)
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| <math>[| F^\$ (p, q) |]</math>
 
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| <math>=\!</math>
                  = {x in X : F^$ (p, q)(x)}
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| <math>[| \underline{(}~p~,~q~\underline{)}^\$ |]</math>
 
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|-
                  = {x in X : -(p, q)-^$ (x)}
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| &nbsp;
 
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| <math>=\!</math>
                  = {x in X : -(p(x), q(x))- }
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| <math>(F^\$ (p, q))^{-1} (\underline{1})</math>
 
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|-
                  = {x in X : p(x) ± q(x)}
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| &nbsp;
 
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| <math>=\!</math>
                  = {x in X : p(x) =/= q(x)}
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| <math>\{~ x \in X ~:~ F^\$ (p, q)(x) ~\}</math>
 
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|-
                  = {x in X : -{P}- (x) =/= -{Q}- (x)}
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| &nbsp;
 
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| <math>=\!</math>
                  = {x in X : x in P <=/=> x in Q}
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| <math>\{~ x \in X ~:~ \underline{(}~p~,~q~\underline{)}^\$ (x) ~\}</math>
 
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|-
                  = {x in X : x in P-Q or x in Q-P}
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| &nbsp;
 
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| <math>=\!</math>
                  = {x in X : x in P-Q |_| Q-P}
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| <math>\{~ x \in X ~:~ \underline{(}~p(x)~,~q(x)~\underline{)} ~\}</math>
 
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|-
                  = {x in X : x in P ± Q}
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| &nbsp;
 
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| <math>=\!</math>
                  = P ± Q         c  X
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| <math>\{~ x \in X ~:~ p(x) + q(x) ~\}</math>
 
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|-
                  = [|p|] ± [|q|] X.
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| &nbsp;
 
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| <math>=\!</math>
Which was to be shown.
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| <math>\{~ x \in X ~:~ p(x) \neq q(x) ~\}</math>
</pre>
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|-
 +
| &nbsp;
 +
| <math>=\!</math>
 +
| <math>\{~ x \in X ~:~ \upharpoonleft P \upharpoonright (x) ~\neq~ \upharpoonleft Q \upharpoonright (x) ~\}</math>
 +
|-
 +
| &nbsp;
 +
| <math>=\!</math>
 +
| <math>\{~ x \in X ~:~ x \in P ~\nLeftrightarrow~ x \in Q ~\}</math>
 +
|-
 +
| &nbsp;
 +
| <math>=\!</math>
 +
| <math>\{~ x \in X ~:~ x \in P\!-\!Q ~\operatorname{or}~ x \in Q\!-\!P ~\}</math>
 +
|-
 +
| &nbsp;
 +
| <math>=\!</math>
 +
| <math>\{~ x \in X ~:~ x \in P\!-\!Q ~\cup~ Q\!-\!P ~\}</math>
 +
|-
 +
| &nbsp;
 +
| <math>=\!</math>
 +
| <math>\{~ x \in X ~:~ x \in P + Q ~\}</math>
 +
|-
 +
| &nbsp;
 +
| <math>=\!</math>
 +
| <math>P + Q ~\subseteq~ X</math>
 +
|-
 +
| &nbsp;
 +
| <math>=\!</math>
 +
| <math>[|p|] + [|q|] ~\subseteq~ X</math>
 +
|-
 +
| &nbsp;
 +
|}
    
==References==
 
==References==
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