MyWikiBiz, Author Your Legacy — Friday January 10, 2025
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67 bytes added
, 19:45, 5 June 2008
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| \begin{quote} | | \begin{quote} |
| $\operatorname{E}A^\circ = [ \operatorname{E}\mathcal{A} ] = [ \mathcal{A}\ \cup\ \operatorname{d}\mathcal{A} ] = [ a_1, \ldots, a_n, \operatorname{d}a_1, \ldots, \operatorname{d}a_n ].$ | | $\operatorname{E}A^\circ = [ \operatorname{E}\mathcal{A} ] = [ \mathcal{A}\ \cup\ \operatorname{d}\mathcal{A} ] = [ a_1, \ldots, a_n, \operatorname{d}a_1, \ldots, \operatorname{d}a_n ].$ |
| + | \end{quote} |
| + | |
| + | This gives $\operatorname{E}A^\circ$ the type: |
| + | |
| + | \begin{quote} |
| + | $[ \mathbb{B}^n \times \mathbb{D}^n ] = (\mathbb{B}^n \times \mathbb{D}^n\ +\!\to \mathbb{B}) = (\mathbb{B}^n \times \mathbb{D}^n, \mathbb{B}^n \times \mathbb{D}^n \to \mathbb{B}).$ |
| \end{quote} | | \end{quote} |
| \end{itemize} | | \end{itemize} |
− |
| |
− | This gives $\operatorname{E}A^\circ$ the type $(\mathbb{B}^n \times \mathbb{D}^n\ +\!\to \mathbb{B}) = (\mathbb{B}^n \times \mathbb{D}^n, \mathbb{B}^n \times \mathbb{D}^n \to \mathbb{B}).$
| |
| | | |
| $\dots$ | | $\dots$ |