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Revision as of 17:32, 6 May 2008
, 17:32, 6 May 2008Modifications
int main()
int main()
{
{
int A = 0;
int A = 0;
int B = 0;
int B = 0;
double discrim = sqrt((B * B) - 4 * A * C);
double discrim = sqrt((B * B) - 4 * A * C);
double imaginary_discrim = sqrt(-((B * B) - 4 * A * C));
double imaginary_discrim = sqrt(-((B * B) - (4 * A * C)));
if (discrim >= 0)
if(discrim >= 0)
{
{
cout<<"The value of the discriminant is: "<<discrim<<"\n";
cout<<"The value of the discriminant is: "<<discrim<<"\n";
if(A != 0)
if(A != 0)
{
{
if(A <0)
if(A < 0)
{
{
A *= -1;
A *= -1;
{
{
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two real solutions are:"<<"\n";
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two real solutions are:"<<"\n";
cout<<"X = "<<(-B + discrim)/(2.0 * A)<<"\n";
cout<<"X = "<<((-B + discrim)/(2.0 * A))<<"\n";
cout<<"X = "<<(-B - discrim)/(2.0 * A)<<"\n";
cout<<"X = "<<((-B - discrim)/(2.0 * A))<<"\n";
}
}
else if (discrim == 0)
else if (discrim == 0)
{
{
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the one real solution is:"<<"\n";
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the one real solution is:"<<"\n";
cout<<"X = "<<-B /(2.0 * A)<<"\n";
cout<<"X = "<<(-B/(2.0 * A))<<"\n";
}
}
else
else
{
{
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two imaginary solutions are:"<<"\n";
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two imaginary solutions are:"<<"\n";
cout<<"X = "<<-B / (2.0 * A)<<" + "<<imaginary_discrim /(2 * A)<<"i"<<"\n";
cout<<"X = "<<(-B/(2.0 * A))<<" + "<<(imaginary_discrim/(2 * A))<<"i"<<"\n";
cout<<"X = "<<-B / (2.0 * A)<<" - "<<imaginary_discrim /(2 * A)<<"i"<<"\n";
cout<<"X = "<<(-B/(2.0 * A))<<" - "<<(imaginary_discrim/(2 * A))<<"i"<<"\n";
}
}
