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Revision as of 04:20, 17 December 2010
, 04:20, 17 December 2010→Version 1. “On the Natural Classification of Arguments” (1867): + text
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−<p>The formula of analogy is as follows: <math>S^{\prime}, S^{\prime\prime}, S^{\prime\prime\prime}</math> are taken at random from such a class that their characters at random are such as <math>P^{\prime}, P^{\prime\prime}, P^{\prime\prime\prime}.</math></p>
+<p>The formula of analogy is as follows: <math>S^{\prime}, S^{\prime\prime}, ~\operatorname{and}~ S^{\prime\prime\prime}</math> are taken at random from such a class that their characters at random are such as <math>P^{\prime}, P^{\prime\prime}, P^{\prime\prime\prime}.</math></p>
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+|
<center>
<center>
<math>\begin{matrix}
<math>\begin{matrix}
−t ~\operatorname{is}~ P^{\prime}, P^{\prime\prime}, P^{\prime\prime\prime},
+t ~\operatorname{is}~ P^{\prime}, P^{\prime\prime}, ~\operatorname{and}~ P^{\prime\prime\prime},
\\[4pt]
\\[4pt]
−S^{\prime}, S^{\prime\prime}, S^{\prime\prime\prime} ~\operatorname{are}~ q;
+S^{\prime}, S^{\prime\prime}, ~\operatorname{and}~ S^{\prime\prime\prime} ~\operatorname{are}~ q;
\\[4pt]
\\[4pt]
\therefore t ~\operatorname{is}~ q.
\therefore t ~\operatorname{is}~ q.
\end{matrix}</math>
\end{matrix}</math>
</center>
</center>
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−<p>Such an argument is double. It combines the two following:
+| <p>Such an argument is double. It combines the two following:
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+|
<center>
<center>
<math>\begin{matrix}
<math>\begin{matrix}
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\end{matrix}</math>
\end{matrix}</math>
</center>
</center>
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+|
+<center>
+<math>\begin{matrix}
+2.
+\\[4pt]
+S^{\prime}, S^{\prime\prime}, S^{\prime\prime\prime} ~\operatorname{are,~for~instance,}~ P^{\prime}, P^{\prime\prime}, P^{\prime\prime\prime},
+\\[4pt]
+t ~\operatorname{is}~ P^{\prime}, P^{\prime\prime}, P^{\prime\prime\prime};
+\\[4pt]
+\therefore ~(\operatorname{By~hypothesis})~ t ~\operatorname{has~the~common~characters~of}~ S^{\prime}, S^{\prime\prime}, S^{\prime\prime\prime},
+\\[4pt]
+S^{\prime}, S^{\prime\prime}, S^{\prime\prime\prime} ~\operatorname{are}~ q;
+\\[4pt]
+\therefore ~(\operatorname{Deductively})~ t ~\operatorname{is}~ q.
+\end{matrix}</math>
+</center>
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