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| Let <math>\mathbb{B} = \{ \operatorname{F}, \operatorname{T} \}</math> be the ''[[boolean domain]]'' of two logical values. The truth table shows the ordered triples of a [[triadic relation]] <math>L \subseteq \mathbb{B} \times \mathbb{B} \times \mathbb{B}\!</math> that is defined as follows: | | Let <math>\mathbb{B} = \{ \operatorname{F}, \operatorname{T} \}</math> be the ''[[boolean domain]]'' of two logical values. The truth table shows the ordered triples of a [[triadic relation]] <math>L \subseteq \mathbb{B} \times \mathbb{B} \times \mathbb{B}\!</math> that is defined as follows: |
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− | : <math>L = \{(p,\ q,\ r) \in \mathbb{B} \times \mathbb{B} \times \mathbb{B}\ :\ Cond (p,\ q)\ = r \}\,.\!</math>
| + | {| align="center" cellspacing="10" width="90%" |
| + | | <math>L = \{ (p, q, r) \in \mathbb{B} \times \mathbb{B} \times \mathbb{B} : \operatorname{Cond}(p, q) = r \}.</math> |
| + | |} |
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| Regarded as a set, this triadic relation is the same thing as the binary operation: | | Regarded as a set, this triadic relation is the same thing as the binary operation: |
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− | : <math>Cond : \mathbb{B} \times \mathbb{B} \to \mathbb{B}\,.\!</math>
| + | {| align="center" cellspacing="10" width="90%" |
| + | | <math>\operatorname{Cond} : \mathbb{B} \times \mathbb{B} \to \mathbb{B}.</math> |
| + | |} |
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| The relationship between <math>Cond\!</math> and <math>L\!</math> exemplifies the standard association that exists between any binary operation and its corresponding triadic relation. | | The relationship between <math>Cond\!</math> and <math>L\!</math> exemplifies the standard association that exists between any binary operation and its corresponding triadic relation. |
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| The conditional sign "<math>\rightarrow\!</math>" denotes the same formal object as the function name "<math>Cond\mbox{ }\!</math>", the only difference being that the first is written infix while the second is written prefix. Thus we have the following equation: | | The conditional sign "<math>\rightarrow\!</math>" denotes the same formal object as the function name "<math>Cond\mbox{ }\!</math>", the only difference being that the first is written infix while the second is written prefix. Thus we have the following equation: |
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− | : <math>(p \rightarrow q) = Cond (p,\ q)\,.\!</math>
| + | {| align="center" cellspacing="10" width="90%" |
| + | | <math>(p \rightarrow q) = \operatorname{Cond}(p, q).</math> |
| + | |} |
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| Consider once again the triadic relation <math>L \subseteq \mathbb{B} \times \mathbb{B} \times \mathbb{B}\!</math> that is defined in the following equivalent fashion: | | Consider once again the triadic relation <math>L \subseteq \mathbb{B} \times \mathbb{B} \times \mathbb{B}\!</math> that is defined in the following equivalent fashion: |
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− | : <math>L = \{(p,\ q,\ Cond (p,\ q))\ :\ (p,\ q) \in \mathbb{B} \times \mathbb{B} \}\,.\!</math>
| + | {| align="center" cellspacing="10" width="90%" |
| + | | <math>L = \{ (p, q, \operatorname{Cond}(p, q) ) : (p, q) \in \mathbb{B} \times \mathbb{B} \}.</math> |
| + | |} |
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− | Associated with the triadic relation <math>L\!</math> is a binary relation <math>L_{..T} \subseteq \mathbb{B} \times \mathbb{B}\!</math> that is called the ''[[image (mathematics)|fiber]]'' of <math>L\!</math> with <math>T\!</math> in the third place. This object is defined as follows: | + | Associated with the triadic relation <math>L\!</math> is a binary relation <math>L_{\underline{~} \underline{~} \operatorname{T}} \subseteq \mathbb{B} \times \mathbb{B}\!</math> that is called the ''[[image (mathematics)|fiber]]'' of <math>L\!</math> with <math>\operatorname{T}</math> in the third place. This object is defined as follows: |
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− | : <math>L_{..T} = \{ (p,\ q) \in \mathbb{B} \times \mathbb{B}\ :\ (p,\ q,\ T) \in L \}\,.\!</math>
| + | {| align="center" cellspacing="10" width="90%" |
| + | | <math>L_{..T} = \{ (p, q) \in \mathbb{B} \times \mathbb{B} : (p, q, \operatorname{T}) \in L \}.</math> |
| + | |} |
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| The same object is achieved in the following way. Begin with the binary operation: | | The same object is achieved in the following way. Begin with the binary operation: |