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Line 2,991: Line 2,991:     
And next we derive the following results:
 
And next we derive the following results:
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:{| cellpadding="4"
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| 'l',
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| =
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| colspan="2" | "lover that is --- of ---"
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|-
  −
|  
  −
| =
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| colspan="2" | B:B:C +, C:C:B +, D:D:O +, E:E:I +, I:I:E +, J:J:D +, O:O:D
  −
|}
      
{| align="center" cellspacing="6" width="90%"
 
{| align="center" cellspacing="6" width="90%"
 
|
 
|
<math>\begin{array}{lll}
+
<math>\begin{array}{l}
\mathit{l},\!\mathit{s}\mathrm{w}
+
\mathit{l}, ~=
& = &
+
\\[6pt]
 +
\text{lover that is}\, \underline{~~~~}\, \text{of}\, \underline{~~~~} ~=
 +
\\[6pt]
 +
(\mathrm{B}\!:\!\mathrm{B}\!:\!\mathrm{C} ~+\!\!,~ \mathrm{C}\!:\!\mathrm{C}\!:\!\mathrm{B} ~+\!\!,~ \mathrm{D}\!:\!\mathrm{D}\!:\!\mathrm{O} ~+\!\!,~ \mathrm{E}\!:\!\mathrm{E}\!:\!\mathrm{I} ~+\!\!,~ \mathrm{I}\!:\!\mathrm{I}\!:\!\mathrm{E} ~+\!\!,~ \mathrm{J}\!:\!\mathrm{J}\!:\!\mathrm{D} ~+\!\!,~ \mathrm{O}\!:\!\mathrm{O}\!:\!\mathrm{D})
 +
\\[12pt]
 +
\mathit{l},\!\mathit{s}\mathrm{w} ~=
 +
\\[6pt]
 
(\mathrm{B}\!:\!\mathrm{B}\!:\!\mathrm{C} ~+\!\!,~ \mathrm{C}\!:\!\mathrm{C}\!:\!\mathrm{B} ~+\!\!,~ \mathrm{D}\!:\!\mathrm{D}\!:\!\mathrm{O} ~+\!\!,~ \mathrm{E}\!:\!\mathrm{E}\!:\!\mathrm{I} ~+\!\!,~ \mathrm{I}\!:\!\mathrm{I}\!:\!\mathrm{E} ~+\!\!,~ \mathrm{J}\!:\!\mathrm{J}\!:\!\mathrm{D} ~+\!\!,~ \mathrm{O}\!:\!\mathrm{O}\!:\!\mathrm{D})
 
(\mathrm{B}\!:\!\mathrm{B}\!:\!\mathrm{C} ~+\!\!,~ \mathrm{C}\!:\!\mathrm{C}\!:\!\mathrm{B} ~+\!\!,~ \mathrm{D}\!:\!\mathrm{D}\!:\!\mathrm{O} ~+\!\!,~ \mathrm{E}\!:\!\mathrm{E}\!:\!\mathrm{I} ~+\!\!,~ \mathrm{I}\!:\!\mathrm{I}\!:\!\mathrm{E} ~+\!\!,~ \mathrm{J}\!:\!\mathrm{J}\!:\!\mathrm{D} ~+\!\!,~ \mathrm{O}\!:\!\mathrm{O}\!:\!\mathrm{D})
 
\\
 
\\
& &
   
\times
 
\times
 
\\
 
\\
& &
   
(\mathrm{C}\!:\!\mathrm{O} ~+\!\!,~ \mathrm{E}\!:\!\mathrm{D} ~+\!\!,~ \mathrm{I}\!:\!\mathrm{O} ~+\!\!,~ \mathrm{J}\!:\!\mathrm{D} ~+\!\!,~ \mathrm{J}\!:\!\mathrm{O})
 
(\mathrm{C}\!:\!\mathrm{O} ~+\!\!,~ \mathrm{E}\!:\!\mathrm{D} ~+\!\!,~ \mathrm{I}\!:\!\mathrm{O} ~+\!\!,~ \mathrm{J}\!:\!\mathrm{D} ~+\!\!,~ \mathrm{J}\!:\!\mathrm{O})
 
\\
 
\\
& &
   
\times
 
\times
 
\\
 
\\
& &
   
(\mathrm{B} ~+\!\!,~ \mathrm{D} ~+\!\!,~ \mathrm{E})
 
(\mathrm{B} ~+\!\!,~ \mathrm{D} ~+\!\!,~ \mathrm{E})
 
\end{array}</math>
 
\end{array}</math>
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