Changes

Line 5,380: Line 5,380:  
|
 
|
 
<math>\begin{array}{lll}
 
<math>\begin{array}{lll}
L_{u \,\text{at}\, 1} & = & \{ (u, x) \in L \}
+
u \cdot L
 +
& = &
 +
L_{u \,\text{at}\, 1}
 
\\[6pt]
 
\\[6pt]
& = & \text{the set of ordered pairs in}~ L ~\text{that have}~ u ~\text{in the 1st place}.
+
& = & \{ (u, x) \in L \}
 +
\\[6pt]
 +
& = &
 +
\text{the set of ordered pairs in}~ L ~\text{that have}~ u ~\text{in the 1st place}.
 
\\[9pt]
 
\\[9pt]
L_{v \,\text{at}\, 2} & = & \{ (x, v) \in L \}
+
L \cdot v
 +
& = &
 +
L_{v \,\text{at}\, 2}
 +
\\[6pt]
 +
& = &
 +
\{ (x, v) \in L \}
 
\\[6pt]
 
\\[6pt]
& = & \text{the set of ordered pairs in}~ L ~\text{that have}~ v ~\text{in the 2nd place}.
+
& = &
 +
\text{the set of ordered pairs in}~ L ~\text{that have}~ v ~\text{in the 2nd place}.
 
\end{array}</math>
 
\end{array}</math>
 
|}
 
|}
Line 5,393: Line 5,404:     
{| align="center" cellspacing="6" width="90%"
 
{| align="center" cellspacing="6" width="90%"
| <math>\mathit{l}^\mathrm{w} ~=~ \bigcap_{x \in W} L_{x \,\text{at}\, 2}</math>
+
| <math>\mathit{l}^\mathrm{w} ~=~ \bigcap_{x \in W} L \cdot x</math>
 
|}
 
|}
  
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