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→‎Step 1: markup
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Working on the remainder of the expression, the next item of business is to abstract <math>y.\!</math>
 
Working on the remainder of the expression, the next item of business is to abstract <math>y.\!</math>
   −
<pre>
   
Notice that:
 
Notice that:
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  (yK)(zS) = (yK)(y((zS)K))
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{| align="center" cellpadding="8" width="90%"
 +
|
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<math>\begin{matrix}
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(y\operatorname{K})(z\operatorname{S})
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& = &
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(y\operatorname{K})(y((z\operatorname{S})\operatorname{K}))
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\\[8pt]
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& = &
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y(\operatorname{K}(((z\operatorname{S})\operatorname{K})\operatorname{S}))
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\end{matrix}</math>
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|}
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            =  y(K(((zS)K)S))
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thus completing the abstraction of <math>y.\!</math>
 
  −
thus completing the abstraction of y.
      +
<pre>
 
Next, work on K(((zS)K)S) to extract z, starting from
 
Next, work on K(((zS)K)S) to extract z, starting from
 
the center (zS)K of the labyrinth and working outward:
 
the center (zS)K of the labyrinth and working outward:
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