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User:Jon Awbrey/SCRATCHPAD
(view source)
Revision as of 17:01, 2 February 2009
618 bytes added
,
17:01, 2 February 2009
→Variant 1
Line 3,095:
Line 3,095:
\upharpoonleft Q \upharpoonright
\upharpoonleft Q \upharpoonright
& = &
& = &
−
\{ (x, y) \in X \times \underline\mathbb{B} ~:~ y
~
=
~
\downharpoonleft s \downharpoonright (x) \}
+
\{ (x, y) \in X \times \underline\mathbb{B} ~:~ y
=
\,
\downharpoonleft s \downharpoonright (x) \}
\end{array}</math>
\end{array}</math>
−
| style="border-left:1px solid black; text-align:center" | <math>\operatorname{R11c~:~\_\_?\_\_}</math>
+
| style="border-left:1px solid black; text-align:center" |
+
<p>
<math>\operatorname{R11c~:~\_\_?\_\_}</math
></p>
+
<p><math>\operatorname{R11c~:~\_\_?\_\_}</math></p>
+
|- style="height:20px"
+
|
+
|
+
|
+
| style="border-left:1px solid black; text-align:center" | <math>::\!</math>
+
|- style="height:60px"
+
|
+
| <math>\operatorname{R11d.}</math>
+
|
+
<math>\begin{array}{lcl}
+
\upharpoonleft Q \upharpoonright
+
& : &
+
X \to \underline\mathbb{B}
+
\\
+
\upharpoonleft Q \upharpoonright (x)
+
& = &
+
\downharpoonleft s \downharpoonright (x)
+
\end{array}</math>
+
| style="border-left:1px solid black; text-align:center" |
+
<p><math>\operatorname{R11d~:~\_\_?\_\_}</math></p>
+
<p><math>\operatorname{R11d~:~\_\_?\_\_}</math></p
>
|}
|}
|}
|}
Jon Awbrey
12,080
edits