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MyWikiBiz, Author Your Legacy — Friday November 01, 2024
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→‎Series 1: use \texttt{...} for logical ops
Line 463: Line 463:  
<math>\begin{array}{rcccccc}
 
<math>\begin{array}{rcccccc}
 
\operatorname{D}(pq)
 
\operatorname{D}(pq)
& = & p & \cdot & q & \cdot & ((\operatorname{d}p)(\operatorname{d}q))
+
& = &
 +
p
 +
& \cdot &
 +
q
 +
& \cdot &
 +
\texttt{(}
 +
\texttt{(} \operatorname{d}p \texttt{)}
 +
\texttt{(} \operatorname{d}q \texttt{)}
 +
\texttt{)}
 
\\[4pt]
 
\\[4pt]
& + & p & \cdot & (q) & \cdot & ~(\operatorname{d}p)~\operatorname{d}q~~
+
& + &
 +
p
 +
& \cdot &
 +
\texttt{(} q \texttt{)}
 +
& \cdot &
 +
\texttt{~}
 +
\texttt{(} \operatorname{d}p \texttt{)}
 +
\texttt{~} \operatorname{d}q \texttt{~}
 +
\texttt{~}
 
\\[4pt]
 
\\[4pt]
& + & (p) & \cdot & q & \cdot & ~~\operatorname{d}p~(\operatorname{d}q)~
+
& + &
 +
\texttt{(} p \texttt{)}
 +
& \cdot &
 +
q
 +
& \cdot &
 +
\texttt{~}
 +
\texttt{~} \operatorname{d}p \texttt{~}
 +
\texttt{(} \operatorname{d}q \texttt{)}
 +
\texttt{~}
 
\\[4pt]
 
\\[4pt]
& + & (p) & \cdot & (q) & \cdot & ~~\operatorname{d}p~~\operatorname{d}q~~
+
& + &
 +
\texttt{(} p \texttt{)}
 +
& \cdot &
 +
\texttt{(}q \texttt{)}
 +
& \cdot &
 +
\texttt{~}
 +
\texttt{~} \operatorname{d}p \texttt{~}
 +
\texttt{~} \operatorname{d}q \texttt{~}
 +
\texttt{~}
 
\end{array}</math>
 
\end{array}</math>
 
|}
 
|}
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