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Directory:Jon Awbrey/Papers/Propositions As Types
(view source)
Revision as of 12:08, 25 March 2009
652 bytes added
,
12:08, 25 March 2009
→Step 1
:
markup
Line 857:
Line 857:
|}
|}
−
<pre>
Filling in the abbreviations:
Filling in the abbreviations:
−
y(xz)
=
x(y(z((
KK
)(
GS
)) ))
+
{| align="center" cellpadding="8" width="90%"
−
+
|
−
=
x(y(z((
KK
)((F((
SK
)S))S)) ))
+
<math>\begin{array}{lll}
−
+
y(xz)
−
=
x(y(z((
KK
)(((S((
KK
)S))((
SK
)S))S)) ))
+
&
=
&
+
x(y(z((
\operatorname{K}\operatorname{K}
)(
\operatorname{G}\operatorname{S}
))
~
))
+
\\[8pt]
+
&
=
&
+
x(y(z((
\operatorname{K}\operatorname{K}
)((
\operatorname{
F
}
((
\operatorname{S}\operatorname{K}
)
\operatorname{
S
}
))
\operatorname{
S
}
))
~
))
+
\\[8pt]
+
&
=
&
+
x(y(z((
\operatorname{K}\operatorname{K}
)(((
\operatorname{
S
}
((
\operatorname{K}\operatorname{K}
)
\operatorname{
S
}
))((
\operatorname{S}\operatorname{K}
)
\operatorname{
S
}
))
\operatorname{
S
}
))
~
))
+
\end{array}</math>
+
|}
Thus we have:
Thus we have:
−
T
=
(
KK
)(((S((
KK
)S))((
SK
)S))S)
+
{| align="center" cellpadding="8" width="90%"
−
</
pre
>
+
|
+
<math>\begin{matrix}
+
\operatorname{
T
}
+
&
=
&
+
(
\operatorname{K}\operatorname{K}
)(((
\operatorname{
S
}
((
\operatorname{K}\operatorname{K}
)
\operatorname{
S
}
))((
\operatorname{S}\operatorname{K}
)
\operatorname{
S
}
))
\operatorname{
S
}
)
+
\end{matrix}
</
math
>
+
|}
===Step 2===
===Step 2===
Jon Awbrey
12,117
edits