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| ===Computation Summary : <math>g(u, v) = \texttt{((u,~v))}</math>=== | | ===Computation Summary : <math>g(u, v) = \texttt{((u,~v))}</math>=== |
| | | |
− | <pre>
| + | Figure 2.1 shows the expansion of <math>g = \texttt{((u,~v))}</math> over <math>[u, v]\!</math> to produce the expression: |
− | Figure 2.1 expands g = ((u, v)) over [u, v] to get | + | |
− | the equivalent exclusive disjunction u v + (u)(v).
| + | {| align="center" cellpadding="8" width="90%" |
| + | | <math>\texttt{uv} ~+~ \texttt{(u)(v)}</math> |
| + | |} |
| + | |
| + | Figure 2.2 shows the expansion of <math>\operatorname{E}g = \texttt{((u + du, ~v + dv))}</math> over <math>[u, v]\!</math> to produce the expression: |
| | | |
− | Figure 2.2 expands Eg = ((u + du, v + dv)) over [u, v] to arrive at
| + | {| align="center" cellpadding="8" width="90%" |
− | Eg = uv((du, dv)) + u(v)(du, dv) + (u)v (du, dv) + (u)(v)((du, dv)).
| + | | <math>\texttt{uv} \cdot \texttt{((du, dv))} + \texttt{u(v)} \cdot \texttt{(du, dv)} + \texttt{(u)v} \cdot \texttt{(du, dv)} + \texttt{(u)(v)} \cdot \texttt{((du, dv))}</math> |
| + | |} |
| | | |
| + | <pre> |
| Eg tells you what you would have to do, from where you are in the | | Eg tells you what you would have to do, from where you are in the |
| universe [u, v], if you want to end up in a place where g is true. | | universe [u, v], if you want to end up in a place where g is true. |