Changes

→‎Note 6: markup
Line 161: Line 161:     
Now, to the Example.
 
Now, to the Example.
 +
 +
Once again, let us begin with a 1-feature alphabet <math>\mathcal{X} = \{ x_1 \} = \{ x \}.</math>  In the discussion that follows I will consider a class of trajectories that are ruled by the constraint that <math>d^k x = 0\!</math> for all <math>k\!</math> greater than some fixed <math>m,\!</math> and I will indulge in the use of some picturesque speech to describes salient classes of such curves.  Given this finite order condition, there is a highest order non-zero difference <math>d^m x\!</math> that is exhibited at each point in the course of any determinate trajectory.
 +
 +
Relative to any point of the corresponding orbit or curve, let us call this highest order differential feature <math>d^m x\!</math> the ''drive'' at that point.  Curves of constant drive <math>d^m x\!</math> are then referred to as ''<math>m^\text{th}\!</math> gear curves''.
    
<pre>
 
<pre>
Once again, let us begin with a 1-feature alphabet !X! = {x_1} = {x}.
  −
In the discussion that follows I will consider a class of trajectories
  −
that are ruled by the constraint that d^k.x = 0 for all k greater than
  −
some fixed m, and I will indulge in the use of some picturesque speech
  −
to describes salient classes of such curves.  Given this finite order
  −
condition, there is a highest order non-zero difference d^m.x that is
  −
exhibited at each point in the course of any determinate trajectory.
  −
Relative to any point of the corresponding orbit or curve, let us
  −
call this highest order differential feature d^m.x the "drive"
  −
at that point.  Curves of constant drive d^m.x are then
  −
referred to as "m^th gear curves".
  −
   
One additional piece of notation will be needed here.
 
One additional piece of notation will be needed here.
 
Starting from the base alphabet !X! = {x}, we define
 
Starting from the base alphabet !X! = {x}, we define
12,089

edits