Changes

→‎Note 20: delete confusing expression
Line 1,764: Line 1,764:  
|}
 
|}
   −
A more fine combing of the second Table brings to mind a rule that partly covers the remaining cases, that is, <math>\texttt{du~=~v}, ~\texttt{dv~=~(u)}.</math>  To vary the formulation, this Table characterizes Orbit&nbsp;2 by means of the following vector equation:  <math>(\texttt{du}, \texttt{dv}) = (\texttt{v}, \texttt{(u)}).</math>  This much information about Orbit&nbsp;2 is also encapsulated by the extended proposition, <math>\texttt{(uv)((du, v))(dv, u)},</math> which says that <math>u\!</math> and <math>v\!</math> are not both true at the same time, while <math>du\!</math> is equal in value to <math>v,\!</math> and <math>dv\!</math> is opposite in value to <math>u.\!</math>
+
A more fine combing of the second Table brings to mind a rule that partly covers the remaining cases, that is, <math>\texttt{du~=~v}, ~\texttt{dv~=~(u)}.</math>  This much information about Orbit&nbsp;2 is also encapsulated by the extended proposition, <math>\texttt{(uv)((du, v))(dv, u)},</math> which says that <math>u\!</math> and <math>v\!</math> are not both true at the same time, while <math>du\!</math> is equal in value to <math>v\!</math> and <math>dv\!</math> is opposite in value to <math>u.\!</math>
    
==Note 21==
 
==Note 21==
12,089

edits