Changes

→‎Proof as semiosis: MathJax treats ~'s in \texttt{ } as printing character rather than blank space
Line 1,382: Line 1,382:  
e_0 & = &
 
e_0 & = &
 
{}^{\backprime\backprime}
 
{}^{\backprime\backprime}
\texttt{(~)}
+
\texttt{( )}
 
{}^{\prime\prime}
 
{}^{\prime\prime}
 
\\[4pt]
 
\\[4pt]
 
e_1 & = &
 
e_1 & = &
 
{}^{\backprime\backprime}
 
{}^{\backprime\backprime}
\texttt{~}
+
\texttt{ }
 
{}^{\prime\prime}
 
{}^{\prime\prime}
 
\\[4pt]
 
\\[4pt]
 
e_2 & = &
 
e_2 & = &
 
{}^{\backprime\backprime}
 
{}^{\backprime\backprime}
\texttt{(} p \texttt{~(} q \texttt{))~(} p \texttt{~(} r \texttt{))}
+
\texttt{(} p \texttt{ (} q \texttt{)) (} p \texttt{ (} r \texttt{))}
 
{}^{\prime\prime}
 
{}^{\prime\prime}
 
\\[4pt]
 
\\[4pt]
 
e_3 & = &
 
e_3 & = &
 
{}^{\backprime\backprime}
 
{}^{\backprime\backprime}
\texttt{(} p \texttt{~(} q~r \texttt{))}
+
\texttt{(} p \texttt{ (} q r \texttt{))}
 
{}^{\prime\prime}
 
{}^{\prime\prime}
 
\\[4pt]
 
\\[4pt]
 
e_4 & = &
 
e_4 & = &
 
{}^{\backprime\backprime}
 
{}^{\backprime\backprime}
\texttt{(} p~q~r \texttt{~,~(} p \texttt{))}
+
\texttt{(} p q r \texttt{ , (} p \texttt{))}
 
{}^{\prime\prime}
 
{}^{\prime\prime}
 
\\[4pt]
 
\\[4pt]
 
e_5 & = &
 
e_5 & = &
 
{}^{\backprime\backprime}
 
{}^{\backprime\backprime}
\texttt{((~(} p \texttt{~(} q \texttt{))~(} p \texttt{~(} r \texttt{))~,~(} p \texttt{~(} q~r \texttt{))~))}
+
\texttt{(( (} p \texttt{ (} q \texttt{)) (} p \texttt{ (} r \texttt{)) , (} p \texttt{ (} q r \texttt{)) ))}
 
{}^{\prime\prime}
 
{}^{\prime\prime}
 
\end{array}\!</math>
 
\end{array}\!</math>
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