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==Bump==
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<div class="nonumtoc">__TOC__</div>
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Huh, looks like I forgot all about doing this work back in Feb 2009. [[User:Jon Awbrey|Jon Awbrey]] 19:00, 2 September 2010 (UTC)
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==Alternate Version : Needs To Be Reconciled==
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====1.3.12.  Syntactic Transformations <big>&#10004;</big>====
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=====1.3.12.1.  Syntactic Transformation Rules=====
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<pre>
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Value Rule 1
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If v, w C B
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then "v = w" is a sentence about <v, w> C B2,
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[v = w] is a proposition : B2 -> B,
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and the following are identical values in B:
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V1a. [ v = w ](v, w)
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V1b. [ v <=> w ](v, w)
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V1c. ((v , w))
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</pre>
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<pre>
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Value Rule 1
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If v, w C B,
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then the following are equivalent:
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V1a. v = w.
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V1b. v <=> w.
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V1c. (( v , w )).
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</pre>
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A rule that allows one to turn equivalent sentences into identical propositions:
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: (S <=> T) <=> ([S] = [T])
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Consider [ v = w ](v, w) and [ v(u) = w(u) ](u)
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<pre>
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Value Rule 1
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If v, w C B,
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then the following are identical values in B:
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V1a. [ v = w ]
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V1b. [ v <=> w ]
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V1c. (( v , w ))
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</pre>
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<pre>
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Value Rule 1
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If f, g : U -> B,
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and u C U
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then the following are identical values in B:
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V1a. [ f(u) = g(u) ]
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V1b. [ f(u) <=> g(u) ]
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V1c. (( f(u) , g(u) ))
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</pre>
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<pre>
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Value Rule 1
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If f, g : U -> B,
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then the following are identical propositions on U:
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V1a. [ f = g ]
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V1b. [ f <=> g ]
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V1c. (( f , g ))$
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</pre>
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<pre>
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Evaluation Rule 1
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If f, g : U -> B
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and u C U,
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then the following are equivalent:
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E1a. f(u) = g(u). :V1a
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::
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E1b. f(u) <=> g(u). :V1b
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::
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E1c. (( f(u) , g(u) )). :V1c
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:$1a
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::
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E1d. (( f , g ))$(u). :$1b
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</pre>
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<pre>
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Evaluation Rule 1
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If S, T are sentences
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about things in the universe U,
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f, g are propositions: U -> B,
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and u C U,
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then the following are equivalent:
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E1a. f(u) = g(u). :V1a
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::
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E1b. f(u) <=> g(u). :V1b
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::
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E1c. (( f(u) , g(u) )). :V1c
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:$1a
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::
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E1d. (( f , g ))$(u). :$1b
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</pre>
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=====1.3.12.2.  Derived Equivalence Relations <big>&#10004;</big>=====
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=====1.3.12.3.  Digression on Derived Relations <big>&#10004;</big>=====
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