Difference between revisions of "Exclusive disjunction"

MyWikiBiz, Author Your Legacy — Friday November 22, 2024
Jump to navigationJump to search
(TeX)
(de-link proposition until we get a proper article)
Line 1: Line 1:
 
<font size="3">&#9758;</font> This page belongs to resource collections on [[Logic Live|Logic]] and [[Inquiry Live|Inquiry]].
 
<font size="3">&#9758;</font> This page belongs to resource collections on [[Logic Live|Logic]] and [[Inquiry Live|Inquiry]].
  
'''Exclusive disjunction''', also known as '''logical inequality''' or '''symmetric difference''', is an operation on two logical values, typically the values of two [[proposition]]s, that produces a value of ''true'' just in case exactly one of its operands is true.
+
'''Exclusive disjunction''', also known as '''logical inequality''' or '''symmetric difference''', is an operation on two logical values, typically the values of two propositions, that produces a value of ''true'' just in case exactly one of its operands is true.
  
 
The [[truth table]] of <math>p ~\operatorname{XOR}~ q</math> (also written as <math>p + q\!</math> or <math>p \ne q\!</math>) is as follows:
 
The [[truth table]] of <math>p ~\operatorname{XOR}~ q</math> (also written as <math>p + q\!</math> or <math>p \ne q\!</math>) is as follows:

Revision as of 16:24, 13 May 2012

This page belongs to resource collections on Logic and Inquiry.

Exclusive disjunction, also known as logical inequality or symmetric difference, is an operation on two logical values, typically the values of two propositions, that produces a value of true just in case exactly one of its operands is true.

The truth table of \(p ~\operatorname{XOR}~ q\) (also written as \(p + q\!\) or \(p \ne q\!\)) is as follows:


\(\text{Exclusive Disjunction}\!\)
\(p\!\) \(q\!\) \(p ~\operatorname{XOR}~ q\)
\(\operatorname{F}\) \(\operatorname{F}\) \(\operatorname{F}\)
\(\operatorname{F}\) \(\operatorname{T}\) \(\operatorname{T}\)
\(\operatorname{T}\) \(\operatorname{F}\) \(\operatorname{T}\)
\(\operatorname{T}\) \(\operatorname{T}\) \(\operatorname{F}\)


The following equivalents can then be deduced:

\[\begin{matrix} p + q & = & (p \land \lnot q) & \lor & (\lnot p \land q) \\ \\ & = & (p \lor q) & \land & (\lnot p \lor \lnot q) \\ \\ & = & (p \lor q) & \land & \lnot (p \land q) \end{matrix}\]

Syllabus

Focal nodes

Template:Col-breakTemplate:Col-breakTemplate:Col-end

Peer nodes

Template:Col-breakTemplate:Col-breakTemplate:Col-end

Logical operators

Template:Col-breakTemplate:Col-breakTemplate:Col-end

Related topics

Template:Col-breakTemplate:Col-breakTemplate:Col-breakTemplate:Col-end

Relational concepts

Template:Col-breakTemplate:Col-breakTemplate:Col-breakTemplate:Col-end

Information, Inquiry

Template:Col-breakTemplate:Col-breakTemplate:Col-breakTemplate:Col-breakTemplate:Col-end

Related articles

Document history

Portions of the above article were adapted from the following sources under the GNU Free Documentation License, under other applicable licenses, or by permission of the copyright holders.

Template:Col-breakTemplate:Col-breakTemplate:Col-end
<sharethis />