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<math>\operatorname{E}f</math> tells you what you would have to do, from where you are in the universe <math>[u, v],\!</math> if you want to end up in a place where <math>f\!</math> is true.  In this case, where the prevailing proposition <math>f\!</math> is <math>\texttt{((u)(v))},</math> the indication <math>\texttt{uv} \cdot \texttt{(du~dv)}</math> of <math>\operatorname{E}f</math> tells you this:  If <math>u\!</math> and <math>v\!</math> are both true where you are, then just don't change both <math>u\!</math> and <math>v\!</math> at once, and you will end up in a place where <math>\texttt{((u)(v))}</math> is true.
 
<math>\operatorname{E}f</math> tells you what you would have to do, from where you are in the universe <math>[u, v],\!</math> if you want to end up in a place where <math>f\!</math> is true.  In this case, where the prevailing proposition <math>f\!</math> is <math>\texttt{((u)(v))},</math> the indication <math>\texttt{uv} \cdot \texttt{(du~dv)}</math> of <math>\operatorname{E}f</math> tells you this:  If <math>u\!</math> and <math>v\!</math> are both true where you are, then just don't change both <math>u\!</math> and <math>v\!</math> at once, and you will end up in a place where <math>\texttt{((u)(v))}</math> is true.
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Figure&nbsp;1.3 shows the expansion of <math>\operatorname{D}f</math> over <math>[u, v]\!</math> to produce the expression:
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{| align="center" cellpadding="8" width="90%"
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| <math>\texttt{uv} \cdot \texttt{du~dv} ~+~ \texttt{u(v)} \cdot \texttt{du(dv)} ~+~ \texttt{(u)v} \cdot \texttt{(du)dv} ~+~ \texttt{(u)(v)} \cdot \texttt{((du)(dv))}</math>
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|}
    
<pre>
 
<pre>
Figure 1.3 expands Df over [u, v] to end up with the formula:
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Df = uv du dv + u(v) du(dv) + (u)v (du)dv + (u)(v)((du)(dv)).
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Df tells you what you would have to do, from where you are in the
 
Df tells you what you would have to do, from where you are in the
 
universe [u, v], if you want to bring about a change in the value
 
universe [u, v], if you want to bring about a change in the value
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