In other words, <math>(S^L)_{ij}\!</math> goes to zero as soon as we find an <math>x \in X</math> such that <math>S_{ix} = 0\!</math> and <math>L_{xj} = 1.\!</math>
+
In other words, <math>(\mathfrak{S}^\mathfrak{L})_{ab} = 0</math> if and only if there exists an <math>x \in X</math> such that <math>\mathfrak{S}_{ax} = 0</math> and <math>\mathfrak{L}_{xb} = 1.</math>