Changes

→‎Stretching Exercises: mathematical markup
Line 2,445: Line 2,445:  
{| align="center" cellpadding="8" width="90%"
 
{| align="center" cellpadding="8" width="90%"
 
|
 
|
<math>\begin{array}{ccccc}
+
<math>\begin{matrix}
 
p
 
p
 
& = &
 
& = &
Line 2,466: Line 2,466:  
(X \to \underline\mathbb{B})^2
 
(X \to \underline\mathbb{B})^2
 
\\
 
\\
\end{array}</math>
+
\end{matrix}</math>
 
|}
 
|}
   −
<pre>
+
Then one has an operator <math>F^\$,</math> the stretch of the connection <math>F\!</math> over <math>X,\!</math> and a proposition <math>F^\$ (p, q),</math> the stretch of <math>F\!</math> to <math>(p, q)\!</math> on <math>X,\!</math> with the following properties:
Then one has an operator F^$, the stretch of the connection F over X,
  −
and a proposition F^$ (p, q), the stretch of F to <p, q> on X, with
  −
the following properties:
     −
| F^$        = -( , )-^$  :  (X -> %B%)^2 -> (X -> %B%)
+
{| align="center" cellpadding="8" width="90%"
 
|
 
|
| F^$ (p, q) = -(p, q)-^$ :   X -> %B%
+
<math>\begin{array}{ccccl}
 +
F^\$
 +
& = &
 +
\underline{(} \ldots, \ldots \underline{)}^\$
 +
& : &
 +
(X \to \underline\mathbb{B})^2 \to (X \to \underline\mathbb{B})
 +
\\
 +
\\
 +
F^\$ (p, q)
 +
& = &
 +
\underline{(}~p~,~q~\underline{)}^\$
 +
& : &
 +
X \to \underline\mathbb{B}
 +
\\
 +
\end{array}</math>
 +
|}
    +
<pre>
 
As a result, the application of the proposition F^$ (p, q) to each x in X
 
As a result, the application of the proposition F^$ (p, q) to each x in X
 
yields a logical value in %B%, all in accord with the following equations:
 
yields a logical value in %B%, all in accord with the following equations:
12,080

edits