Derek Elder: Modifications

2008-05-06T17:32:58Z

Modifications

Derek Elder: start of page

2007-11-01T23:34:05Z

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<pre>
#include <iostream>
#include <cmath>
using namespace std;

double sqrt(int discrim)
{
return sqrt(double(discrim));
}

int main()
{

int A = 0;
int B = 0;
int C = 0;

cout<<"Please enter a value for A: ";
cin>>A;
cout<<"Please enter a value for B: ";
cin>>B;
cout<<"Please enter a value for C: ";
cin>>C;

double discrim = sqrt((B * B) - 4 * A * C);
double imaginary_discrim = sqrt(-((B * B) - 4 * A * C));

if (discrim >= 0)
{
cout<<"The value of the discriminant is: "<<discrim<<"\n";
}
else
{
cout<<"The value of the discriminant is: "<<imaginary_discrim<<"i"<<"\n";
}

if(A != 0)
{
if(A <0)
{
A *= -1;
}

if (discrim > 0)
{
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two real solutions are:"<<"\n";
cout<<"X = "<<(-B + discrim)/(2.0 * A)<<"\n";
cout<<"X = "<<(-B - discrim)/(2.0 * A)<<"\n";
}
else if (discrim == 0)
{
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the one real solution is:"<<"\n";
cout<<"X = "<<-B /(2.0 * A)<<"\n";
}
else
{
cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two imaginary solutions are:"<<"\n";
cout<<"X = "<<-B / (2.0 * A)<<" + "<<imaginary_discrim /(2 * A)<<"i"<<"\n";
cout<<"X = "<<-B / (2.0 * A)<<" - "<<imaginary_discrim /(2 * A)<<"i"<<"\n";
}

}
else
cout<<"There is no solution for the equation when A = 0."<<"\n";

return 0;
}
</pre>

@@ Line 11: / Line 11: @@
 int main()
+{
 	int A = 0;
 	int B = 0;
@@ Line 24: / Line 23: @@
 	double discrim = sqrt((B * B) - 4 * A * C);
-	double imaginary_discrim = sqrt(-((B * B) - 4 * A * C));
+	double imaginary_discrim = sqrt(-((B * B) - (4 * A * C)));
-	if (discrim >= 0)
+	if(discrim >= 0)
+	{
 		cout<<"The value of the discriminant is: "<<discrim<<"\n";
@@ Line 37: / Line 36: @@
 	if(A != 0)
+	{
-		if(A <0)
+		if(A < 0)
+		{
 			A *= -1;
@@ Line 45: / Line 44: @@
+		{
 			cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two real solutions are:"<<"\n";
-			cout<<"X = "<<(-B + discrim)/(2.0 * A)<<"\n";
+			cout<<"X = "<<((-B + discrim)/(2.0 * A))<<"\n";
-			cout<<"X = "<<(-B - discrim)/(2.0 * A)<<"\n";
+			cout<<"X = "<<((-B - discrim)/(2.0 * A))<<"\n";
+		}
 		else if (discrim == 0)
+		{
 			cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the one real solution is:"<<"\n";
-			cout<<"X = "<<-B /(2.0 * A)<<"\n";
+			cout<<"X = "<<(-B/(2.0 * A))<<"\n";
+		}
 		else
+		{
 			cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two imaginary solutions are:"<<"\n";
-			cout<<"X = "<<-B / (2.0 * A)<<" + "<<imaginary_discrim /(2 * A)<<"i"<<"\n";
+			cout<<"X = "<<(-B/(2.0 * A))<<" + "<<(imaginary_discrim/(2 * A))<<"i"<<"\n";
-			cout<<"X = "<<-B / (2.0 * A)<<" - "<<imaginary_discrim /(2 * A)<<"i"<<"\n";
+			cout<<"X = "<<(-B/(2.0 * A))<<" - "<<(imaginary_discrim/(2 * A))<<"i"<<"\n";
+		}

Directory:Derek Elder/Programs/Quadratic Formula - Revision history

Derek Elder: Modifications

Derek Elder: start of page